3 years ago

∠A and ∠B are vertical angles with m∠A=x and m∠B=4x−30 . What is m∠A ?

Mathematics

1 answer:

True [87]3 years ago

7 0

4x-30=180
180-30
4x=150
150/4
37.5
x=37.5

You might be interested in

What is the solution to the equation below? Enter the answer in the format p=#, keep your answer as a fraction if necessary. -2/

Scorpion4ik [409]

Let's solve your equation step-by-step.

-2/3p+ 1/6= 7/10

Answer:

p= -4/5

6 0

3 years ago

Point Q' (3,2) is the image of Q (6,4) under a translation

maks197457 [2]

$x-value= 6-3= 3$ Find the x-value difference

$y-value=4-2=2$ Find the y-value difference

<u><em>*(The Answer)*=</em></u> The translation is the point shifted 3 units to the right and 2 units up.

6 0

3 years ago

Read 2 more answers

There are 7 fourth-grade classes at Grant Elementary. Each class has 28 students. About how many students are in the fourth grad

DaniilM [7]

7*28= 196 closest answer to that is 210

7 0

3 years ago

Use a linear approximation to estimate the number (125.07)2/3

Ivahew [28]

Let $f(x)=x^{2/3}$ . You have $f(125)=(125)^{2/3}=(5^3)^{2/3}=5^2=25$ .

Taking the derivative, you get

$f'(x)=\dfrac2{3x^{1/3}}\implies f'(125)=\dfrac2{3(125)^{1/3}}=\dfrac2{3\times5}=\dfrac2{15}$

The linear approximation to $f(x)$ near $x=125$ is given by

$L(x)=f(125)+f'(125)(x-125)\approx f(x)$

So the value of $(125.07)^{2/3}$ can be estimated as

$L(125.07)=f(125)+f'(125)(125.07-125)$
$L(125.07)=25+\dfrac2{15}(0.07)=25.009333\ldots$

8 0

3 years ago

Can someone please answer this?

Artyom0805 [142]

Marked in the picture I sent

4 0

3 years ago

∠A and ​ ∠B ​ are vertical angles with m∠A=x and m∠B=4x−30 . What is m∠A ?

∠A and ∠B are vertical angles with m∠A=x and m∠B=4x−30 . What is m∠A ?