The probability of any particular sequence of N flips of a fair coin is 2^(-N).
Your probability of the given sequence of 3 coin flips is
2^-3 = 1/8
Ok. Could I have a picture of the question? :)
Answer:
Step-by-step explanation:
To write Five times the sum of a number and one you first make "a number" into a variable. In this case let's call it
n
.
Next let's create the sum of a number and one. This would be:
n
+
1
.
Then to get five times this number we need to multiple this expression by five to get:
5
⋅
(
n
+
1
)
