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FinnZ [79.3K]
3 years ago
15

Solve the equation for the unknown variable.

Mathematics
2 answers:
Georgia [21]3 years ago
8 0

Answer:

d = -3

Step-by-step explanation:

Given the equation:

d^3 = -27

Solve for d:

Take both sides cube root we have;

d =\sqrt[3]{-27}

We can write 27 as:

27 = 3 \cdot 3 \cdot 3 = 3^3

then;

d = \sqrt[3]{-3^3}

Using the rules:

\sqrt[n]{a^n} = a

\sqrt[3]{-1} = -1

then;

d = -\sqrt[3]{3^3} = -3

therefore, the unknown variable d is, -3

EleoNora [17]3 years ago
4 0

Answer:

-3

Step-by-step explanation:

this is the anwer............ ben solo once said: let the numbers dicrease make them negetive if you have to:D lol

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Please help me on this because I'm not sure if it's a decimal or not
anzhelika [568]
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3 0
3 years ago
11. In a sample of n=6, five individuals all have scores of X=10 and the sixth person has a score of x=16. What is the mean for
ahrayia [7]

Answer:

11

Step-by-step explanation:

Given that in a sample of n=6, five individuals all have scores of X=10 and the sixth person has a score of x=16

i.e. the data entries are

10,10,10,10,10,16

Sum = 66

No of items n = 6

Average = sum/no of entries

=\frac{66}{6} \\=11

Average is 11.

mean of this sample is 11

8 0
3 years ago
Solve the equation p^2 + 4p = 1 by completing the square.
igor_vitrenko [27]

Answer:

p = -2 ±sqrt( 5)

Step-by-step explanation:

p^2 + 4p = 1

Take the coefficient of p

4

Divide by 2

4/2 =2

Square it

2^2 = 4

Add it to each side

p^2 + 4p+4 = 1+4

(p+2) ^2 = 5

Take the square root of each side

sqrt((p+2) ^2) =±sqrt( 5)

p+2 = ±sqrt( 5)

Subtract 2 from each side

p+2-2 = -2 ±sqrt( 5)

p = -2 ±sqrt( 5)

7 0
3 years ago
What is the 15th term of the sequence -4, -2, 0, 2, …?What is the 15th term of the sequence -4, -2, 0, 2, …?
Dmitriy789 [7]

Answer:

24

Step-by-step explanation:

6 0
3 years ago
The quadratic function f(x) has a turning point at (-3,6). the quadratic y=2/3f(x)+3 would have a turning point of
NARA [144]

Answer:

C. (-3,11)

Step-by-step explanation:

Tp is (-3,6) implies the quadratic could have been

f(x) = (x+3)²+6

(2/3)f(x) = (2/3)[(x+3)²+6]

= (2/3)(x+3)²+4

(2/3)f(x)+3 = (2/3)(x+3)²+4+3

= (2/3)(x+3)²+7

Tp at (-3,7)

Alternately,

No change in domain so x remains-3

(2/3)f(x) changes y from 6 to 4 (6×2/3)

+3 increases the y by 3

i.e 4+3 = 7

So, (-3,7)

4 0
3 years ago
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