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kari74 [83]
3 years ago
6

A contractor combined x tons of a gravel mixture that contained 10 percent gravel G, by weight, with y tons of a mixture that co

ntained 2 percent gravel G, by weight, to produce z tons of a mixture that was 5 percent gravel G, by weight. What is the value of x ?
Mathematics
1 answer:
White raven [17]3 years ago
3 0

Answer:

The value of x would be \frac{3}{5}y or \frac{3}{8}z

Step-by-step explanation:

Given,

x tons of 10% gravel G mixture is mixed with y ton of 2% gravel G to obtain  5% gravel mixture,

Thus, gravel G in x ton + gravel in y ton = gravel G in the resultant mixture,          

⇒ 0.1x + 0.02y = 0.05(x+y),

0.1x - 0.05x = 0.05y - 0.02y

0.05x = 0.03y

\implies x = \frac{0.03}{0.05}y=\frac{3}{5}y----(1)

Now, resultant mixture is z ton,

i.e. z=x+y

\implies y = z - x

From equation (1),

x=\frac{3}{5}(z-x) = \frac{3}{5}z-\frac{3}{5}x

x+\frac{3}{5}x=\frac{3}{5}z

\frac{8}{5}x=\frac{3}{5}z

x=\frac{3}{8}z

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