Answer:
i think its (0,-2)
Step-by-step explanation:
Answer:
c(h) = 50 +10h
c(4) = 90 . . . . . it costs $90 to rent the truck for 4 hours
Step-by-step explanation:
The problem statement tells you the total charge is the sum of $50 and a charge of $10 per hour. That is, for h hours, the total charge is ...
c = 50 + 10h
In functional form, this is ...
c(h) = 50 +10h . . . . . . total charger for a rental of h hours
__
The function value with an input of 4 is ...
c(4) = 50 +10·4
c(4) = 90
Since the input is the number of hours of rental, and the function value is the total charge, this represents the total charge for a rental of 4 hours.
Point B is used for both triangles and is located in the same place, which means triangle ABC was rotated at point B
Then triangle ABC was reduced in size to make DBE, which is called a dilation.
The first drop down should be Rotation and then dilation.
The second drop down should be Similar.
The answer is triangle ACD is congruent to triangle ABD.
Use main logarithm properties:
![\log_ab^k=k\log_ab;\\ \\\log_ab+\log_ac=\log_abc;\\ \\\log_ab-\log_ac=\log_a\dfrac{b}{c}.](https://tex.z-dn.net/?f=%5Clog_ab%5Ek%3Dk%5Clog_ab%3B%5C%5C%20%5C%5C%5Clog_ab%2B%5Clog_ac%3D%5Clog_abc%3B%5C%5C%20%5C%5C%5Clog_ab-%5Clog_ac%3D%5Clog_a%5Cdfrac%7Bb%7D%7Bc%7D.)
Then
1.
![\dfrac{1}{4}\ln x=\ln x^{\frac{1}{4}}.](https://tex.z-dn.net/?f=%5Cdfrac%7B1%7D%7B4%7D%5Cln%20x%3D%5Cln%20x%5E%7B%5Cfrac%7B1%7D%7B4%7D%7D.)
2.
![\dfrac{3}{10}\ln (x+2)=\ln (x+2)^{\frac{3}{10}}.](https://tex.z-dn.net/?f=%5Cdfrac%7B3%7D%7B10%7D%5Cln%20%28x%2B2%29%3D%5Cln%20%28x%2B2%29%5E%7B%5Cfrac%7B3%7D%7B10%7D%7D.)
3.
![\ln (x-2)-\dfrac{3}{10}\ln (x+2)=\ln \dfrac{x-2}{(x+2)^{\frac{3}{10}}}.](https://tex.z-dn.net/?f=%5Cln%20%28x-2%29-%5Cdfrac%7B3%7D%7B10%7D%5Cln%20%28x%2B2%29%3D%5Cln%20%5Cdfrac%7Bx-2%7D%7B%28x%2B2%29%5E%7B%5Cfrac%7B3%7D%7B10%7D%7D%7D.)
4.
![5\left(\ln (x-2)-\dfrac{3}{10}\ln (x+2)\right)=5\ln \dfrac{x-2}{(x+2)^{\frac{3}{10}}}=\ln \dfrac{(x-2)^2}{(x+2)^{\frac{3}{2}}}.](https://tex.z-dn.net/?f=5%5Cleft%28%5Cln%20%28x-2%29-%5Cdfrac%7B3%7D%7B10%7D%5Cln%20%28x%2B2%29%5Cright%29%3D5%5Cln%20%5Cdfrac%7Bx-2%7D%7B%28x%2B2%29%5E%7B%5Cfrac%7B3%7D%7B10%7D%7D%7D%3D%5Cln%20%5Cdfrac%7B%28x-2%29%5E2%7D%7B%28x%2B2%29%5E%7B%5Cfrac%7B3%7D%7B2%7D%7D%7D.)
5.
![\dfrac{1}{4}\ln x+5\left(\ln (x-2)-\dfrac{3}{10}\ln (x+2)\right)=\ln x^{\frac{1}{4}}+\ln \dfrac{(x-2)^2}{(x+2)^{\frac{3}{2}}}=\ln \dfrac{x^{\frac{1}{4}}(x-2)^5}{(x+2)^{\frac{3}{2}}}=\\ \\=\ln \dfrac{\sqrt[4]{x}(x-2)^5}{\sqrt{(x+2)^3}}.](https://tex.z-dn.net/?f=%5Cdfrac%7B1%7D%7B4%7D%5Cln%20x%2B5%5Cleft%28%5Cln%20%28x-2%29-%5Cdfrac%7B3%7D%7B10%7D%5Cln%20%28x%2B2%29%5Cright%29%3D%5Cln%20x%5E%7B%5Cfrac%7B1%7D%7B4%7D%7D%2B%5Cln%20%5Cdfrac%7B%28x-2%29%5E2%7D%7B%28x%2B2%29%5E%7B%5Cfrac%7B3%7D%7B2%7D%7D%7D%3D%5Cln%20%5Cdfrac%7Bx%5E%7B%5Cfrac%7B1%7D%7B4%7D%7D%28x-2%29%5E5%7D%7B%28x%2B2%29%5E%7B%5Cfrac%7B3%7D%7B2%7D%7D%7D%3D%5C%5C%20%5C%5C%3D%5Cln%20%5Cdfrac%7B%5Csqrt%5B4%5D%7Bx%7D%28x-2%29%5E5%7D%7B%5Csqrt%7B%28x%2B2%29%5E3%7D%7D.)
Answer: correct choice is B