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klio [65]
3 years ago
13

Help me with 8 through 12 please and thank you only 4 questions

Mathematics
2 answers:
tatuchka [14]3 years ago
7 0
what ??there’s no picture
Anvisha [2.4K]3 years ago
3 0
Wait theres no picture?im confused
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Given: KL ║ NM , LM = 45, m∠M = 50° KN ⊥ NM , NL ⊥ LM Find: KN and KL
Mice21 [21]

Answer:

KL=45\tan 50^{\circ}\sin 50^{\circ}\approx 41.08\\ \\KN=45\sin 50^{\circ}\approx 34.47

Step-by-step explanation:

Given:

KL ║ NM ,

LM = 45

m∠M = 50°

KN ⊥ NM  

NL ⊥ LM

Find: KN and KL

1. Consider triangle NLM. This is a right triangle, because NL ⊥ LM. In this triangle,

LM = 45

m∠M = 50°

So,

\tan \angle M=\dfrac{\text{opposite leg}}{\text{adjacent leg}}=\dfrac{NL}{LM}=\dfrac{NL}{45}\\ \\NL=45\tan 50^{\circ}

Also

m\angle LNM=90^{\circ}-50^{\circ}=40^{\circ} (angles LNM and M are complementary).

2. Consider triangle NKL. This is a right triangle, because KN ⊥ NM . In this triangle,

NL=45\tan 50^{\circ}

m\angle KLN=m\angle LNM=40^{\circ} (alternate interior angles)

m\angle KNL=90^{\circ}-40^{\circ}=50^{\circ} (angles KNL and KLN are complementary).

So,

\sin \angle KNL=\dfrac{\text{opposite leg}}{\text{hypotenuse}}=\dfrac{KL}{LN}=\dfrac{KL}{45\tan 50^{\circ}}\\ \\KL=45\tan 50^{\circ}\sin 50^{\circ}\approx 41.08

and

\cos \angle KNL=\dfrac{\text{adjacent leg}}{\text{hypotenuse}}=\dfrac{KN}{LN}=\dfrac{KN}{45\tan 50^{\circ}}\\ \\KN=45\tan 50^{\circ}\cos 50^{\circ}=45\sin 50^{\circ}\approx 34.47

3 0
3 years ago
Read 2 more answers
No one is answering i posted this question 2 times, this is my 3rd time please answer.
Dahasolnce [82]

Answer:

13

Step-by-step explanation:

First, fill in 3 boxes of the table using the given information (blue numbers on the attached table)

"Of the 32 students that have a cell phone, 19 students do not have a tablet."

The top row of the table is students who have a cell phone.  Therefore, place 19 in the box in this row that is in the "no tablet" column.

"Of the 70 students that have a tablet, 57 students do not have a cell phone."

The first column of the table is students who have a tablet.  Therefore, place 57 in the box in the 2nd row of this column.

"11 students do not have a cell phone or a tablet."

Find the "no cell phone" row and the "no tablet" column and place 11 in the box that coincides.

We can calculate the blank totals using addition (shown by green numbers on the attached table)

  • Total students with no cell phone = 57 + 11 = 68
  • Total students with no tablet = 19 + 11 = 30

To calculate the number of students who have a cell phone AND a tablet:

⇒ Total students with a cell phone <em>minus</em> students with a cell phone but no tablet

⇒ 32 - 19 = 13

4 0
2 years ago
I need some help with a math problem
alina1380 [7]

Answer:

3m-25>68

Step-by-step explanation:

Your Welcome

Btw- I didn't write a step by step explanation cause it doesn't need one.

4 0
3 years ago
When is g(x) = 0 for the function g(x) = 5⋅2^3x + 4?
SashulF [63]
The answer should be when X=1
Hope this helped u out if not sorry
:D

6 0
3 years ago
All of the following ratios are equivalent except<br> 4<br> 8 to 12<br> 2:3<br> 09
Gemiola [76]

Answer:

The answer is 2:3 as the order is different. Simplified the first option is 2:3, the second one: 2:3, the third one 3:2 and the fourth one 2:3

7 0
3 years ago
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