|a| = b gives
a =b or a = -b
so,
|-x| = -10
gives
-x = -10 or -x = 10
x = 10, -10
now let us verify,
when x = 10, |-10| = +10 and it is not = -10
so, x= 10 is NOT a solution.
when x = -10, |-(-10)| = |10| = 10 and it is not = -10
so, x= -10 is NOT a solution.
hence, this equation does not have a solution.
If we know that |...| can never be negative, we can directly deduce that this equation does not have any solution.
Graph one: A01- 100 miles
A03 (a)- 50
Answer:
f(-4) = 72, f(x + 5) = 3x² + 23x + 36
Step-by-step explanation:
f(-4) = 3(-4)² - 7(-4) - 4
= 48 - (-28) - 4
f(-4) = 72
f(x + 5) = 3(x + 5)² - 7(x + 5) - 4
= 3(x + 5)(x + 5) - 7(x + 5) - 4
= 3(x² + 10x + 25) - 7(x + 5) - 4
= 3x² + 30x + 75 - 7x - 35 - 4
f(x + 5) = 3x² + 23x + 36
Answer:
magnitude is always postive
so, it will be +2.5 , so C
This is how I got the answer it’s c
