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alexira [117]
2 years ago
13

Abes apples orchard plants both green apple trees and red apple trees this planting will include 21 red apple trees and 18 green

apple trees what is the ratio of green apple trees and red apple trees
Mathematics
1 answer:
Xelga [282]2 years ago
4 0

Answer:

The ratio of green apples to red apples is .

Step-by-step explanation:

Given,

Number of red apples = 21

Number of green apples = 18

We have to find out the ratio of green apples to red apples.

Solution,

For finding the ratio we have to divide the number of green apples to the number of red apples.

So, we can frame the above sentence as;

Ratio = number of green apples/number of red apples

Now substituting the values, we get;

Ratio= 18/21 = 6/7

Hence The ratio of green apples to red apples is . 6/7

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Write the phrase "the product of 19 and a number" as a mathematical expression.
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A candidate for a US Representative seat from Indiana hires a polling firm to gauge her percentage of support among voters in he
mojhsa [17]

Answer:

(A) The minimum sample size required achieve the margin of error of 0.04 is 601.

(B) The minimum sample size required achieve a margin of error of 0.02 is 2401.

Step-by-step explanation:

Let us assume that the percentage of support for the candidate, among voters in her district, is 50%.

(A)

The margin of error, <em>MOE</em> = 0.04.

The formula for margin of error is:

MOE=z_{\alpha /2}\sqrt{\frac{p(1-p)}{n}}

The critical value of <em>z</em> for 95% confidence interval is: z_{\alpha/2}=1.96

Compute the minimum sample size required as follows:

MOE=z_{\alpha /2}\sqrt{\frac{p(1-p)}{n}}\\0.04=1.96\times \sqrt{\frac{0.50(1-0.50)}{n}}\\(\frac{0.04}{1.96})^{2} =\frac{0.50(1-0.50)}{n}\\n=600.25\approx 601

Thus, the minimum sample size required achieve the margin of error of 0.04 is 601.

(B)

The margin of error, <em>MOE</em> = 0.02.

The formula for margin of error is:

MOE=z_{\alpha /2}\sqrt{\frac{p(1-p)}{n}}

The critical value of <em>z</em> for 95% confidence interval is: z_{\alpha/2}=1.96

Compute the minimum sample size required as follows:

MOE=z_{\alpha /2}\sqrt{\frac{p(1-p)}{n}}\\0.02=1.96\times \sqrt{\frac{0.50(1-0.50)}{n}}\\(\frac{0.02}{1.96})^{2} =\frac{0.50(1-0.50)}{n}\\n=2401.00\approx 2401

Thus, the minimum sample size required achieve a margin of error of 0.02 is 2401.

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