Question

Which equation represents a line that passes through (–2, 4) and has a slope of StartFraction 2 Over 5 EndFraction.?

Answer 1

Answer:

y - 4 = (2/5)(x + 2)

Step-by-step explanation:

Here we're told that the desired line passes through (h, k):  (-2, 4) and that it has a slope of m = 2/5.

Using the point-slope form of the equation of a straight line, we get:

y - k = m(x-h)  =>  y - 4 = (2/5)(x + 2)

Answer 2

Answer:

 $y=\frac{2}{5}x+\frac{24}{5}$

Step-by-step explanation:

We are given a point (-2,4)

$(x_1,y_1)=(-2,4)$

Slope = m $=\frac{2}{5}$

General equation of point slope form : $y-y_1=m(x-x_1)$

Substitute the values :

Equation : $y-4=\frac{2}{5}(x-(-2))$

                 $y-4=\frac{2}{5}(x+2)$

                 $y-4=\frac{2}{5}x+\frac{4}{5}$

                 $y=\frac{2}{5}x+\frac{4}{5}+4$

                 $y=\frac{2}{5}x+\frac{24}{5}$

Hence equation represents a line that passes through (–2, 4) and has a slope 2/5 is   $y=\frac{2}{5}x+\frac{24}{5}$