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vlabodo [156]
3 years ago
13

3x-6/x-2 Show your answer!!

Mathematics
1 answer:
zmey [24]3 years ago
6 0
\frac{3x - 6}{x - 2} = \frac{3(x-2)}{x-2}  = 3
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Which of these following equations solve for x in the two pictures
Roman55 [17]

Answer:

X-14 / 2 = 24

Step-by-step explanation:

X-14 / 2 = 24

X-14 / 2 = 24

7 0
3 years ago
Can somebody please help me like neowwwww!!!!
stepladder [879]

--Answer--

The second one, fourth, and fifth.

--Explanation--

1. - 6.283...

2. 7.142...

3. 6.928...

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2 years ago
What is the ratio of 4.3
Nookie1986 [14]
The answer to the question What is the ratio of 4.3 is 4:3
6 0
3 years ago
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Suppose a company needs temporary passwords for the trial of a new payroll software. Each password will have one digit followed
Alekssandra [29.7K]

Answer:  The required number of passwords that can be created is 175760.

Step-by-step explanation:  Given that a company needs temporary passwords for the trial of a new payroll software.

Each password will have one digit followed by three letters and the letters can be repeated.

We are to find the number of passwords that can be created using this format.

For the one digit in the password, we have 10 options, 0, 1, 2, 3, 4, 5, 6, 7, 8 and 9.

Since there are 26 letters in English alphabet and letters can be repeated, so the number of options for 3 letters is

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3 0
3 years ago
Please help me with these!
Dvinal [7]

Answer:

Step-by-step explanation:

A1. C = 104°, b = 16, c = 25

Law of Sines: B = arcsin[b·sinC/c} ≅ 38.4°

A = 180-C-B = 37.6°

Law of Sines: a = c·sinA/sinC ≅ 15.7

A2. B = 56°, b = 17, c = 14

Law of Sines: C = arcsin[c·sinB/b] ≅43.1°

A = 180-B-C = 80.9°

Law of Sines: a = b·sinA/sinB ≅ 20.2

B1.  B = 116°, a = 11, c = 15

Law of Cosines: b = √(a² + c² - 2ac·cosB) = 22.2

A = arccos{(b²+c²-a²)/(2bc) ≅26.5°

C = 180-A-B = 37.5°

B2. a=18, b=29, c=30

Law of Cosines: A = arccos{(b²+c²-a²)/(2bc) ≅ 35.5°

Law of Cosines: B = arccos[(a²+c²-b²)/(2ac) = 69.2°

C = 180-A-B = 75.3°

6 0
2 years ago
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