Answer:
C. 61
Step-by-step explanation:
Two sides are equal, so the triangle is an isosceles triangle.
Both base angles are equal.
Angles in a triangle add up to 180 degrees.
58 + x + x = 180
58 + 2x = 180
2x = 122
x = 61
AG and GB must be congruent and CG and GD must be congruent as well
SOH,CAH, TOA so it would be TANGENT since it would be Opposite over Adjacent. Tan(15) = 9/a put Tan(15) onto your calculator it would be .267949 round that to .27 = 9/a cross multiply
a = 33.588. C is the correct answer.
Hello from MrBillDoesMath!
Answer:
108 cm^2
Discussion:
The area of the logo =
area of Trapezoid on top (I) + area of triangle on bottom (II)
I = (1/2) h ( b1 + b2) h = altitude, b1, b2 = bases
= (1/2) 6 ( 6 + 12)
= (1/2) 6 ( 18)
= 54
II = (1/2) b h
= (1/2) (12) ( 15 - 6) => altitude of triangle = 15 - 6 NOT (1/2) 15
= 54
I + II= 54 + 54 = 108
Thank you,
MrB
Answer:
Given, ∠MNP=107 degree.
Therefore, ∠QPN= 107 degree. [as, MN=PQ]
We know, sum of four angles of a quadrilateral is 360 degree.
And as MN=PQ, ∠NMQ=∠MQP.
Therefore, ∠MQP= {360 degree-( 107degree+ 107 degree)}/2
=( 360 degree-214 degree)/2
= 146 degree/2
=73 degree.
hope this will help you.
Step-by-step explanation:
