Question

The temperature of a cooling liquid over time can be modeled by the exponential function T(x) = 60(1/2)^(x/30) + 20, where T(x) is the temperature in degrees Celsius, and x is the elapsed time in minutes. Graph the function and determine how long it takes for the temperature to reach 28°C. What was the initial temperature?

Answer 1

Based on the scenario, the initial temperature would be :

28 = (60) (1/2)^x/30 + 20
 
(60) (1/2)^0/30 + 20 = 60 + 20 = 

80 C

Hope this helps