The number of defective modems in the inventory is 20%⋅ 30 + 8%⋅ 50 = 10 (out of 80).
Note that the number of defectives in the inventory is fixed, i.e., we are not told that there
is 1
8 probability that a modem in the inventory is defective, but rather that exactly 1
8
of
all modems are defective. The probability that exactly two modems in a random sample
of five are defective is = 0.102
Solution: Let
be the number of adult ticket's.
The number of child ticket 
We are given, that an adult ticket cost's $10 and child ticket costs $6. Also the church luncheon made $842.
Therefore,





Therefore, the number of adult ticket's sold = 35
And the number of child ticket's sold = 2 x 35 + 12 = 70 + 12 = 82
Step-by-step explanation:
50-6(4)
50-24
=26
plug in 50 "b"
then you plug in 4 for "a"
Answer:
5 times as large
Step-by-step explanation:
The ratio of the two numbers tells you how many times as large one is as the other:
