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Eva8 [605]
4 years ago
12

A system of equations is graphed on a coordinate plane.

Mathematics
1 answer:
lys-0071 [83]4 years ago
6 0
The answer is (1,4) because it is closer to those numbers
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A store has 80 modems in its inventory, 30 coming from source a and the remainder from source
Mrrafil [7]
The number of defective modems in the inventory is 20%⋅ 30 + 8%⋅ 50 = 10 (out of 80). Note that the number of defectives in the inventory is fixed, i.e., we are not told that there is 1 8 probability that a modem in the inventory is defective, but rather that exactly 1 8 of all modems are defective. The probability that exactly two modems in a random sample of five are defective is = 0.102
5 0
3 years ago
A church luncheon made $842. Adult tickets cost $10 each and children's tickets cost $6 each. The number of children was 12 more
Orlov [11]

Solution: Let x be the number of adult ticket's.

The number of child ticket =2x+12

We are given, that an adult ticket cost's $10 and child ticket costs $6. Also the church luncheon made $842.

Therefore,

x \times 10 + (2x+12)6=842

10x+12x+72=842

22x=842-72

22x=770

x=\frac{770}{22}=35

Therefore, the number of adult ticket's sold = 35

And the number of child ticket's sold = 2 x 35 + 12 = 70 + 12 = 82

3 0
4 years ago
There are 600 students at a middle school. If 60% of the students are girls, how many students at the middle school are girls?
mash [69]

Answer:

360!

Step-by-step explanation:

4 0
3 years ago
Read 2 more answers
Evaluate when a= 4 and b = 50. <br>b-6a​
frosja888 [35]

Step-by-step explanation:

50-6(4)

50-24

=26

plug in 50 "b"

then you plug in 4 for "a"

3 0
4 years ago
Read 2 more answers
5?10 5 5, dot, 10, start superscript, 5, end superscript is how many times as large as 1\cdot10^51?10 5 1, dot, 10, start supers
max2010maxim [7]

Answer:

  5 times as large

Step-by-step explanation:

The ratio of the two numbers tells you how many times as large one is as the other:

\dfrac{5\cdot 10^5}{1\cdot 10^5}=\dfrac{5}{1}\cdot\dfrac{10^5}{10^5}=5

4 0
3 years ago
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