For domain 2x sqrt(2+x)>0
x>0,2+x>0,x>-2 combining
we get x>2
f'(x)=[1/{2x sqrt(2+x)}][{2x/(2 sqrt(2+x))}+2 sqrt(2+x)]
I believe if I’m not wrong the answer should be B 1/6
"if you break down a $1 bill, it is 4 quarters. If you add the 4 quarters to the other 3 then you will get the sum of 7."
Hope this helps!
