Answer:
You can prove this statement as follows:
Step-by-step explanation:
An odd integer is a number of the form
where
. Consider the following cases.
Case 1. If
is even we have:
.
If we denote by
we have that
.
Case 2. if
is odd we have:
.
If we denote by
we have that 
This result says that the remainder when we divide the square of any odd integer by 8 is 1.
12/2+4-2*3
According to the order of operations, evaluate division and multiplication first.
6+4-6
Then add and subtract from left to right
10-6
4
Final answer: A
The answer to this problem is 45
The answer is B. Hope this helps!(: