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Naya [18.7K]
3 years ago
9

Suppose that y varies inversely with x.Give x=3 when y=8 Find y when x=4

Mathematics
1 answer:
Alex73 [517]3 years ago
4 0

Answer:

y=10.667

Step-by-step explanation:

cross multiply

3/8=4/y

4*8/3

=32/3

y=10.667

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Use the Distributive Property to expand this expression.
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Answer:

C is the correct answer

Step-by-step explanation:

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3 years ago
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10.045+2.673+105.95 to the nearest whole number and then estimate the sum
horsena [70]

Answer:

119

Step-by-step explanation:

The nearest whole numbers from those listed are

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The estimated sum = 119

The actual sum is 118.668

When you are doing a test, being able to estimate is a very powerful skill. 119 is close enough to the actual answer that you know your actual answer is likely correct.

5 0
4 years ago
Mei has 15 oranges, 9 peaches, and 18 pears. She wants to put all of the fruit into decorative baskets. Each basket must have th
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3 years ago
How do I find the correct Domain.
Damm [24]

Answer:

The domain of a function is the set of all possible inputs for the function. For example, the domain of f(x)=x² is all real numbers, and the domain of g(x)=1/x is all real numbers except for x=0. We can also define special functions whose domains are more limited.

Step-by-step explanation:

Another way to identify the domain and range of functions is by using graphs. Because the domain refers to the set of possible input values, the domain of a graph consists of all the input values shown on the x-axis. The range is the set of possible output values, which are shown on the y-axis.

hope this helps a little

5 0
3 years ago
Assume we need to estimate the mean of a normally-distributed population with great accuracy. Specifically, for significance lev
bulgar [2K]

Answer:

n = 2662.56\sigma^2                                

Step-by-step explanation:

We are given the following in the question:

Significance level = 0.01

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Formula for sample size:

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Putting these values in the equation:

n = \displaystyle\frac{(2.58)^2\sigma^2}{(0.05)^2} = 2662.56\sigma^2

So, the above expression helps us to calculate the sample size so that the width of the confidence interval is no larger than 0.1 for different sample variances.

4 0
4 years ago
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