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Verizon [17]
2 years ago
12

Can someone please help me with this

Mathematics
1 answer:
schepotkina [342]2 years ago
5 0

Answer:

y=25

2 of the y's = 50 in total

Step-by-step explanation:

180-115=x

x=65

180-90-65=y

y=25

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sergiy2304 [10]

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it woupld be the lterr if 7 and 65 and juj hyhy st

Step-by-step explanation:

5 0
3 years ago
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How do you write 996 as a fraction, mixed number, or whole number in simplest form?
sveticcg [70]

To convert a mixed number to its lowest form, one needs to change the mixed number into an improper fraction and then reduce this improper fraction to the lowest possible fraction. To do these conversions, one needs to perform a few calculations. One also has to understand the definitions of "mixed number," "improper fraction" and "proper fraction."

A proper fraction is a fraction that has a lower number in the numerator and a higher number in denominator, such as the fraction three-fourths. An improper fraction is the inverse of this, which entails the higher number in numerator and lower number in the denominator, like 5/3. A mixed number is a whole number with a fraction, such as 1 3/4.

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5 0
3 years ago
Read 2 more answers
$5 PAYPAL + BRAINLIEST TO ANSWER THS
expeople1 [14]

Answer:

Quadratic Equation:

3x^2=2x +5

\text{Standard Form: } 3x^2-2x-5=0

From the standard form of a Quadratic Function, we get:

a=3,\:b=-2,\:c=-5

Discriminant:

\Delta=\left(-2\right)^2-4\cdot \:3\left(-5\right)

\Delta=\left(-2\right)^2+4\cdot \:3\cdot \:5

\Delta=64

From the discriminant, we conclude that the equation will have two real solutions.

State that:

b^2-4ac

b^2-4ac =0:\text{The equation has 1 real solution}

b^2-4ac >0:\text{The equation has 2 real solutions}

By the way, solving the equation given:

$x=\frac{2\pm\sqrt{64}}{2\cdot \:3}$

$x=\frac{2\pm\sqrt{64}}{6}$

$x=\frac{2\pm8}{6}$

$x_{1} =\frac{10}{6}=\frac{5}{3}  $

$x_{2}=\frac{-6}{6} =-1$

5 0
3 years ago
Please answer the one u can do
Charra [1.4K]
I believe #7 is D) 5.5 x W 
3 0
3 years ago
Read 2 more answers
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den301095 [7]
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Hope this helps!
3 0
2 years ago
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