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alekssr [168]
3 years ago
6

Can someone help me with 4(4x+5)?

Mathematics
1 answer:
ycow [4]3 years ago
5 0
The answer would be 16x + 20
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Which ordered pair is a solution of this equation? -9x-5y=12
Sidana [21]
-9x-5y=12
C) (2, -6)  -18+30=12
7 0
3 years ago
6. The height of a triangle is 2 units more than the base. The area of the triangle is 10 square units. Find
Harrizon [31]

Answer:

4.24

Step-by-step explanation:

First, let's set up the equation: \frac{2+x^2}{2}=10

Next, clear the fraction by multiplying both sides by 2:2*(\frac{2+x^2}{2}=10)=2+x^2=20

Then, subtract 2 from both sides: x^2=18

Finally, take a square root of both sides and round: \sqrt{x^2=18} =(Rounded to the nearest hundredth) 4.24

7 0
2 years ago
Niu has decorated x cards. He started with 24 stickers, and he used 4 stickers per card. Which expressions can we use to describ
Kisachek [45]

Answer:

24-4x

Step-by-step explanation:

We have been given that Niu has decorated x cards. He started with 24 stickers and he used 4 stickers per card. So stickers used in x cards will be 4x.

As initial number of stickers was 24, so we can find number of stickers left after decorating x cards by subtracting number of stickers used in x cards from 24.

\text{Number of stickers that Niu has left}=24-4x

Therefore, the expression 24-4x will represent the number of stickers that Niu has left after decorating x cards.


7 0
3 years ago
Read 2 more answers
The function f(x)=(x-5)^2 +2 is not one-to-one. Identify a restricted domain that makes the function one-to-one, and find the in
Anon25 [30]

We have been given a quadratic function f(x)=(x-5)^{2} +2 and we need to restrict the domain such that it becomes a one to one function.

We know that vertex of this quadratic function occurs at (5,2).

Further, we know that range of this function is [2,\infty).

If we restrict the domain of this function to either (-\infty,5] or [5,\infty), it will become one to one function.

Let us know find its inverse.

y=(x-5)^{2}+2

Upon interchanging x and y, we get:

x=(y-5)^{2}+2

Let us now solve this function for y.

(y-5)^{2}=x-2\\
y-5=\pm \sqrt{x-2}\\
y=5\pm \sqrt{x-2}\\

Hence, the inverse function would be f^{-1}(x)=5+\sqrt{x-2} if we restrict the domain of original function to [5,\infty) and the inverse function would be f^{-1}(x)=5-\sqrt{x-2} if we restrict the domain to (-\infty,5].

8 0
2 years ago
What is 5 times 5 <br> and also what is 5 plus 5 bc im rly silly
timofeeve [1]

Answer:

5 x 5 = 25 and 5 + 5 = 10

Step-by-step explanation:

You multiply 5 Five times.

So you get 5,10,15,20,25!

The answer is 25

You add 5 two times.

So you get 5 plus 5!

5,6,7,8,9,10!

The answer is 10

Hope this helped!

~Oreo!!

5 0
3 years ago
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