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lilavasa [31]
3 years ago
10

Which percent is equivalent to 3 2/5

Mathematics
2 answers:
SOVA2 [1]3 years ago
3 0

3  \frac{2}{5} = 3.4

Multiply this by 100 to get your answer!

3.4 × 100 = 34%

So, therefore, 34% is your final answer.

Which percent is equivalent to 3 2/5? 34% is!

↑   ↑   ↑  Hope this helps! :D

SIZIF [17.4K]3 years ago
3 0
To answer this first we will convert 3 2/5 to an improper fraction. Then we will turn  that improper fraction to a decimal, and last but not least, turn that decimal to a percentage. lets do it:-

3 2/5

To change a mixed number to a improper fraction we will multiply the denominator by the whole number and add the answer to that to the numerator. Then the answer to that will be our new numerator and the new denominator will stay the same as before.

3 2/5

5 × 3 = 15
15 + 2 = 17

New improper fraction:-
 
17/5.

To change this into a decimal we will divide the numerator by the denominator.  
17 ÷ 5 = 3.4

Now to change a decimal to a percentage we have to multiply the decimal by 100. 

3.4 × 100 = 340
340%

So, the percentage (percent) which is equivalent to 3 2/5 is 340%.

Hope i helped ya!! xD <span />
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Plzz anyone solve all answers plzzzzzzzz​
algol13

You posted a lot of problems here. In the future please only post one problem at a time. Thank you.

I'll do the first two problems to get you started. Hopefully it will help you finish off the rest of the questions.

==========================================

Problem 1

{18, a, b, -3} is an arithmetic sequence or arithmetic progression (AP).

This means we have some number d added on to each term to get the next term.

first term = 18

second term = first term + d = 18+d = a

third term = second term + d = (18+d)+d = 18+2d = b

fourth term = third term + d = (18+2d)+d = 18+3d = -3

----

Let's solve that last equation for d

18+3d = -3

18+3d-18 = -3-18

3d = -21

3d/3 = -21/3

d = -7

----

The value d = -7 tells us to add -7 to each term to get the next term. In other words, we subtract 7 from each term to get the next term

first term = 18

second term = first term + d = 18+d = 18+(-7) = 18-7 = 11

third term = second term + d = 11+d = 11+(-7) = 11-7 = 4

fourth term = third term + d = 4+d = 4+(-7) = 4-7 = -3

----

We see that a = 11 and b = 4 are the second and third terms respectively.

Therefore, a+b = 11+4 = 15

-------------

<h3>Answer: 15</h3>

==========================================

Problem 2

A multiple of 4 is in the form 4*n for some integer n, ie n is a whole number.

We want to know which values of 4*n are between 10 and 250.

----

Divide both 10 and 250 by 4 to get the following

10/4 = 2.5

250/4 = 62.5

If n = 2, then 4*n = 4*2 = 8 is not between 10 and 250; however n = 3 will make 4*n = 4*3 = 12 to be between 10 and 250. We see that n = 3 is the smallest possible allowed value.

If n = 62, then 4*n = 4*62 = 248 is between 10 and 250; while n = 63 will make 4*n too big because 4*63 = 252. The largest n can get is n = 62

----

The question posed in question 2 is equivalent to asking the following: "How many values are in the set {3, 4, 5, ..., 60, 61, 62}?"

You could count all of the values in the set, but that exercise is very tedious busywork. There's a much faster way. First lets consider the set below

{a, a+1, a+2, ..., b-2, b-1, b}

where a,b are integers. Basically this set starts at 'a', counts up until we get to 'b'. The handy formula

c = b-a+1

will provide the exact count of values in the set {a, a+1, a+2, ..., b-2, b-1, b}

----

In this case, a = 3 and b = 62, making

c = b-a+1

c = 62-3+1

c = 60

There are 60 values in the set {3, 4, 5, ..., 60, 61, 62}

There are 60 multiples of four that are between 10 and 250.

-------------

<h3>Answer: 60</h3>
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