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Finger [1]
3 years ago
13

es%20%20-%205" id="TexFormula1" title=" \frac{1}{2} \times - 2 + \frac{1}{3} \times - 5" alt=" \frac{1}{2} \times - 2 + \frac{1}{3} \times - 5" align="absmiddle" class="latex-formula">
how do I solve this?​
Mathematics
1 answer:
WINSTONCH [101]3 years ago
8 0
<h3>Here is your Answer </h3>

\frac{1}{2} \times - 2 + \frac{1}{3} \times - 5 \\  \\  = \frac{1}{ \cancel2} \times  \cancel{- 2} + \frac{1}{3} \times - 5 \\  \\  = 1 \times  - 1 +  \frac{1}{3}  \times  - 5 \\  \\  =  - 1 + ( -  \frac{5}{3} ) \\  \\   =  - 1 -  \frac{5}{3}  \\  \\  =  \frac{ - 3 - 5}{3}  \\  \\  =  \frac{ - 8}{3}  =  - 2 \frac{2}{3}

<h3>Hope This Helps You</h3>

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Can someone help me with this pls. I’ll give brainliest
nasty-shy [4]

Answer:

26

Step-by-step explanation:

a triangle is 180 degrees add 120 + 34 to get 154

180 -154 = 26

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the least square yard is 15 yards by 15 yards. how many feet of fencing will they need to buy to fence in all four sides
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3 years ago
What is (2-7x)+34-6-(758+8)
pickupchik [31]

Step-by-step explanation:

2- 7x + 34 - 6-(766)

2-7x + 34 - 6 - 766

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5 0
3 years ago
The line width used for semiconductor manufacturing is assumed to be normally distributed with a mean of 0.5 micrometer and a st
Alinara [238K]

Answer:

There is a 0.82% probability that a line width is greater than 0.62 micrometer.

Step-by-step explanation:

Problems of normally distributed samples can be solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by

Z = \frac{X - \mu}{\sigma}

After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X. The sum of the probabilities is decimal 1. So 1-pvalue is the probability that the value of the measure is larger than X.

In this problem

The line width used for semiconductor manufacturing is assumed to be normally distributed with a mean of 0.5 micrometer and a standard deviation of 0.05 micrometer, so \mu = 0.5, \sigma = 0.05.

What is the probability that a line width is greater than 0.62 micrometer?

That is P(X > 0.62)

So

Z = \frac{X - \mu}{\sigma}

Z = \frac{0.62 - 0.5}{0.05}

Z = 2.4

Z = 2.4 has a pvalue of 0.99180.

This means that P(X \leq 0.62) = 0.99180.

We also have that

P(X \leq 0.62) + P(X > 0.62) = 1

P(X > 0.62) = 1 - 0.99180 = 0.0082

There is a 0.82% probability that a line width is greater than 0.62 micrometer.

3 0
3 years ago
3 minus a number is equal 8
krek1111 [17]

Answer

<h2>11</h2>

Step-by-step explanation:

well is you know 8+8=16 then....3-11=8

6 0
3 years ago
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