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Finger [1]
3 years ago
13

es%20%20-%205" id="TexFormula1" title=" \frac{1}{2} \times - 2 + \frac{1}{3} \times - 5" alt=" \frac{1}{2} \times - 2 + \frac{1}{3} \times - 5" align="absmiddle" class="latex-formula">
how do I solve this?​
Mathematics
1 answer:
WINSTONCH [101]3 years ago
8 0
<h3>Here is your Answer </h3>

\frac{1}{2} \times - 2 + \frac{1}{3} \times - 5 \\  \\  = \frac{1}{ \cancel2} \times  \cancel{- 2} + \frac{1}{3} \times - 5 \\  \\  = 1 \times  - 1 +  \frac{1}{3}  \times  - 5 \\  \\  =  - 1 + ( -  \frac{5}{3} ) \\  \\   =  - 1 -  \frac{5}{3}  \\  \\  =  \frac{ - 3 - 5}{3}  \\  \\  =  \frac{ - 8}{3}  =  - 2 \frac{2}{3}

<h3>Hope This Helps You</h3>

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3 years ago
Angle (theta) is in standard position. If (8,-15) is on the terminal ray of angle (theta), find the values of the trigonometric
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Answer:

\sin \theta =\frac{-15}{17}\\cos \theta =\frac{8}{17}\\\tan  \theta =\frac{-15}{8}\\\csc \theta =\frac{-17}{15}\\\sec \theta =\frac{17}{8}\\\cot \theta =\frac{-8}{15}

Step-by-step explanation:

Given: (8,-15) is on the terminal ray of angle

To find: All the trigonometric ratios

Solution:

Trigonometry is a  branch of mathematics that explain relationship between the sides and angles of triangles.

If (x, y) lies on the terminal side of  θ  then r=\sqrt{x^2+y^2}

r=\sqrt{(8)^2+(-15)^2}=\sqrt{64+225}=\sqrt{289}=17 units

\sin \theta =\frac{y}{r}=\frac{-15}{17}\\cos \theta =\frac{x}{r}=\frac{8}{17}\\\tan  \theta =\frac{y}{x}=\frac{-15}{8}\\\csc \theta =\frac{1}{\sin \theta }=\frac{-17}{15}\\\sec \theta =\frac{1}{cos \theta}=\frac{17}{8}\\\cot \theta =\frac{1}{\tan  \theta}=\frac{-8}{15}

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