Believe it or not, :), the width of the ribbon needs to be known to get the right answer. If the ribbon had an infinitely small width the ribbon needed would just be the perimeter.
P=2(L+W)
P=2(12+15)
P=54 in
However an infinitely small width is not something that has any practical application. For example, if the width of the ribbon were 1/2 in.
P=2((L+1)+W)
P=2(16+12)
P=56 in So the perimeter increased by 2 in when the ribbon was only 1/2 in wide.
The "infinitely small" width and the perimeter of 54 in is only a decent approximation if the ribbon were a very thin string.
Answer:
3
Step-by-step explanation:
because divide Pt from both sides to get r=i/(pt)
Well, for 20 you just add them, to get
. For 21, you do a substraction:
. It'd take him quite some time (does this one even have zeros? :)) )
Answer:
6x 6x
I might be wrong
Step-by-step explanation:
I hope that's the answer
