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julia-pushkina [17]
3 years ago
11

Manny made 4 pizzas to share among himself and 6 friends How much pizza will each person get? Well reread the question and ask y

ourself what is the question is asking you. This problem does not ask you to solve it. In fact, you have to put the number listed as a improper faction. It ask you how much pizza will each person get. If he have 6 friends including himself that means the denominator will be 7 and the numerator is 4. The answer will be 4/7. Hope that explains to you all!
Mathematics
2 answers:
Assoli18 [71]3 years ago
6 0
....... shouldn't that be a question instead of an answer? Well, I guess it is what it is, and I understand it thx anyways. (=^\/^=)
murzikaleks [220]3 years ago
4 0
Each Person Gets 4 slices Equaly. :)
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How many five card hands can<br> be dealt from a standard deck of<br> 52 cards?
Law Incorporation [45]

Answer:

2

Step-by-step explanation:

7 0
3 years ago
Boxes of raisins are labeled as containing 22 ounces. Following are the weights, in the ounces, of a sample of 12 boxes. It is r
ZanzabumX [31]

Answer:

A 90% confidence interval for the mean weight is [21.78 ounces, 21.98 ounces].

Step-by-step explanation:

We are given the weights, in the ounces, of a sample of 12 boxes below;

Weights (X): 21.88, 21.76, 22.14, 21.63, 21.81, 22.12, 21.97, 21.57, 21.75, 21.96, 22.20, 21.80.

Firstly, the pivotal quantity for finding the confidence interval for the population mean is given by;

                         P.Q.  =  \frac{\bar X-\mu}{\frac{s}{\sqrt{n} } }  ~ t_n_-_1

where, \bar X = sample mean weight = \frac{\sum X}{n} = 21.88 ounces

            s = sample standard deviation = \sqrt{\frac{\sum (X-\bar X)^{2} }{n-1} }  = 0.201 ounces

            n = sample of boxes = 12

            \mu = population mean weight

<em>Here for constructing a 90% confidence interval we have used a One-sample t-test statistics because we don't know about population standard deviation.</em>

<u>So, 90% confidence interval for the population mean, </u>\mu<u> is ;</u>

P(-1.796 < t_1_1 < 1.796) = 0.90  {As the critical value of t at 11 degrees of

                                                  freedom are -1.796 & 1.796 with P = 5%}  

P(-1.796 < \frac{\bar X-\mu}{\frac{s}{\sqrt{n} } } < 1.796) = 0.90

P( -1.796 \times {\frac{s}{\sqrt{n} } } < {\bar X-\mu} < 1.796 \times {\frac{s}{\sqrt{n} } } ) = 0.90

P( \bar X-1.796 \times {\frac{s}{\sqrt{n} } } < \mu < \bar X+1.796 \times {\frac{s}{\sqrt{n} } } ) = 0.90

<u>90% confidence interval for</u> \mu = [ \bar X-1.796 \times {\frac{s}{\sqrt{n} } } , \bar X+1.796 \times {\frac{s}{\sqrt{n} } } ]

                                        = [ 21.88-1.796 \times {\frac{0.201}{\sqrt{12} } } , 21.88+1.796 \times {\frac{0.201}{\sqrt{12} } } ]

                                        = [21.78, 21.98]

Therefore, a 90% confidence interval for the mean weight is [21.78 ounces, 21.98 ounces].

8 0
3 years ago
The sum of two numbers is 60 and the difference is 18. what are the numbers?
makvit [3.9K]

x+y=60 and x-y=18

x is 39 and y is 21.

5 0
3 years ago
I need help on this.​
Murrr4er [49]

Answer:

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Step-by-step explanation:

since it says "in all" that means u have to add them up

6,836 + 4,206 = 11,042

7 0
3 years ago
Find the surface area
horsena [70]
Formula: SA = 2πr² + 2πrh
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SA = 2π6² + 2π*6*40 = 72π + 480π = 552π (in²)

SA = 552π = 552*3.14 = 1733.28 (in²)
Answer: 1733.28.
4 0
2 years ago
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