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VikaD [51]
3 years ago
10

What is 6 x 13/3.....

Mathematics
2 answers:
IgorLugansk [536]3 years ago
7 0

26 is the answer ;)

hope that helps

Wewaii [24]3 years ago
3 0

6 x 13/3=

78/3

divide top and bottom by 3

26/1

26

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a motorboat travels 305km in 5 hours going upstream and 651km in 7 hours going downstream. What is the rate of the boat in still
Ghella [55]
Recall your d = rt, distance = rate * time.

b = speed rate of the boat.

c = speed rate of the current.


keeping in mind that, as the boat goes Upstream, against the current, it's speed is not "b", but is really " b - c ", because the current is subtracting speed from it.

likewise, when the boat is going Downstream, because is going with the current, is really going faster at " b + c ".

\bf \begin{array}{lccclll}
&\stackrel{km}{distance}&\stackrel{kmh}{rate}&\stackrel{hours}{time}\\
&------&------&------\\
Upstream&305&b-c&5\\
Downstream&651&b+c&7
\end{array}
\\\\\\
\begin{cases}
305=(b-c)(5)\implies 61=b-c\implies 61+c=\boxed{b}\\
651=(b+c)(7)\implies 93=b+c\\
----------------------\\
93=\boxed{61+c}+c
\end{cases}
\\\\\\
93=61+2c\implies 32=2c\implies \cfrac{32}{2}=c\implies 16=c

what is the speed of the boat?  well, 61 + c = b.
6 0
4 years ago
How to solve 105x2 +66x - 72 = 0 algebraically. Show work please
trapecia [35]

Answer:

Do pemdas, (parentheses, exponents, multiplication, division, addition and subtraction). But do whatever is first, which in this case is multiplication.

Step-by-step explanation:

Write the equation out.

    105 x 2 + 66x -72 = ?

    105 x 2 = 210

     210 + 66x - 72

    210 + 66x = 276x

     276x - 72 = 204

      ? = 204

5 0
3 years ago
Let U = {q, r, s, t, u, v, w, x, y, z} A = {q, s, u, w, y} B = {q, s, y, z} C = {v, w, x, y, z}. List the elements in the set: A
gtnhenbr [62]

Answer:

A \cup C=\left \{  \text{q, s, u, v, w, x, y, z} \right \}

Step-by-step explanation:

Given: \text{U}=\left \{\text{q, r, s, t, u, v, w, x, y, z} \right \}, \text{A}=\left \{\text{q, s, u, w, y} \right \}, \text{B}=\left \{\text{q, s, y, z} \right \},

\text{C}=\left \{\text{v, w, x, y, z} \right \}.

To find: The elements in the set A \cup C.

Solution:

We have,

\text{U}=\left \{\text{q, r, s, t, u, v, w, x, y, z} \right \}

\text{A}=\left \{\text{q, s, u, w, y} \right \}

\text{B}=\left \{\text{q, s, y, z} \right \}

\text{C}=\left \{\text{v, w, x, y, z} \right \}

Now, A \cup C will contain all the elements in the set A and all the elements in set C.

So, A \cup C=\left \{  \text{q, s, u, v, w, x, y, z} \right \}.

Hence, A \cup C=\left \{  \text{q, s, u, v, w, x, y, z} \right \}.

7 0
3 years ago
A quaderlateral has the following angle measurements :100,90,45, and?
Andrews [41]
The other angle would be 35
7 0
4 years ago
HELP ME THIS IS URGENT I WILL BE GIVING OUT 29 POINTS IF ANYONE ANSWERS EARLY
Pepsi [2]

Answer:

D

Step-by-step explanation:

-7 + 13 equal 6 so thats the answer

3 0
3 years ago
Read 2 more answers
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