Answer: 4
Step-by-step explanation:
The asymptote of g(x) is the aymptote of f(x) shifted six units up
Answer:
Step-by-step explanation:
v=Q-P
v=(5,1,0)
u=v/(magnitude of v)=(5,1,0)/(\sqrt{5^2+1^2+0^2)
u=(5/5.09,1/5.09,0)
v=Q-P
v=(1,1,0)
u=v/(magnitude of v)=(1,1,0)/(\sqrt{1^2+1^2+0^2)
u=(1/
,1/,0)
Answer:
-10 degrees
Step-by-step explanation:
24+8=32
32-(7 x 6)= 32-42=-10
Answer:
The ball shall keep rising tills its velocity becomes zero. Let it rise to a height h feet from point of projection.
Step-by-step explanation:
Let us take the point of projection of the ball as origin of the coordinate system, the upward direction as positive and down direction as negative.
Initial velocity u with which the ball is projected upwards = + 120 ft/s
Uniform acceleration a acting on the ball is to acceleration due to gravity = - 32 ft/s²
The ball shall keep rising tills its velocity becomes zero. Let it rise to a height h feet from point of projection.
Using the formula:
v² - u² = 2 a h,
where
u = initial velocity of the ball = +120 ft/s
v = final velocity of the ball at the highest point = 0 ft/s
a = uniform acceleration acting on the ball = -32 ft/s²
h = height attained
Substituting the values we get;
0² - 120² = 2 × (- 32) h
=> h = 120²/2 × 32 = 225 feet
The height of the ball from the ground at its highest point = 225 feet + 12 feet = 237 feet.
