3 years ago

What is the length of the diagonal AC in the rectangle below?

2 answers:

8 0

Find lengths of BC and DC.

Then use Pythagorean Theorem to find BD (the hypotenuse of right triangle DCB). So Pythag here would be:

$BC^2+DC^2=BD^2$

See attached picture for full work.

ella [17]3 years ago

6 0

I used the distance formula to find the length of diagonal AC.

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Solve the system of equations below

DENIUS [597]

Answer:

The answer is B. (-7,-2)

Step-by-step explanation:

Multiply the first equation by 7,and multiply the second equation by -6.

7(−3x+6y=9)

−6(5x+7y=−49)

Becomes:

−21x+42y=63

−30x−42y=294

Add these equations to eliminate y:

−51x=357

Then solve−51x=357for x:

−51x=357 Divide both sides by -51

x=-7

Write down an original equation:

−3x+6y=9

Substitute−7forxin−3x+6y=9:

(−3)(−7)+6y=9

6y+21=9(Simplify both sides of the equation)

6y+21+−21=9+−21(Add -21 to both sides)

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y=-2

4 0

3 years ago

To the nearest hundredth, how many cm are in 52 in? (1 in = 2.54 cm)

Vikki [24]

There are 132.08cm in 52 inches

4 0

3 years ago

Read 2 more answers

ABCD is a rectangle ,its diagonals meet at O.If AO = 5x+1 and BO = 4x+9,find the length of the diagonals .(lengths in cm).

Sergeu [11.5K]

Answer:

82 cm

Step-by-step explanation:

In rectangles diagonals are equal and bisect each other

AO = BO

5x + 1 = 4x + 9

Subtract 1 from both sides

5x = 4x + 9 -1

5x = 4x + 8

Subtract 4x from both the sides

5x - 4x = 8

x = 8

AO = 5x + 1

= 5*8 +1

= 40 + 1

AO= 41 cm

Diagonal = 2*41 = 82 cm

7 0

3 years ago

What is the side lenth of a cube that has a volume of 27

Marat540 [252]

The anwer is 3. The volume of a cube is lwh. 3 x 3 x 3 = 27

8 0

3 years ago

1 /3 + 1 /9 / (7/10 * 5 / 4 )

Ludmilka [50]

Answer:

0.46

Hope it helps..

have a great day : )

7 0

3 years ago