Ask question

Ask question

All categories

2 years ago

6

Arthur wrote that 15 – 14.7 = 3.

1 answer:

PilotLPTM [1.2K]2 years ago

8 0

3 is incorrect because 14.7 + 3 = 17.7
The answer of 15 - 14.7 = 0.3

You might be interested in

can anyone PLZZZ help with Geometry go to my profile to see which i need help with ill give the brainliest to the correct answer

Alexxx [7]

Answer:

SUREEEEEEEEE!

Step-by-step explanation:

8 0

3 years ago

A swimming pool is 50 meters long,15 meters wide,and 3 meters deep. What is the volume of the pool

steposvetlana [31]

Answer: 2,250 $m^{3}$

Step-by-step explanation:

Volume of the pool is given by : Length X breadth X height

V = 50 X 15 X 3

V = 2,250

5 0

3 years ago

The caplan family was going to New York City to ring in the New Year. 16 family members each paid $341 for their plane ticket to

Usimov [2.4K]

1 persona pagaba 341 por ida y 298 por venido lo que significa que 1 persona paga en total= 639
si son 16 seria= 639*16=10224 en total

3 0

3 years ago

Determine formula of the nth term 2, 6, 12 20 30,42

nalin [4]

Check the forward differences of the sequence.

If $\{a_n\} = \{2,6,12,20,30,42,\ldots\}$ , then let $\{b_n\}$ be the sequence of first-order differences of $\{a_n\}$ . That is, for n ≥ 1,

$b_n = a_{n+1} - a_n$

so that $\{b_n\} = \{4, 6, 8, 10, 12, \ldots\}$ .

Let $\{c_n\}$ be the sequence of differences of $\{b_n\}$ ,

$c_n = b_{n+1} - b_n$

and we see that this is a constant sequence, $\{c_n\} = \{2, 2, 2, 2, \ldots\}$ . In other words, $\{b_n\}$ is an arithmetic sequence with common difference between terms of 2. That is,

$2 = b_{n+1} - b_n \implies b_{n+1} = b_n + 2$

and we can solve for $b_n$ in terms of $b_1=4$ :

$b_{n+1} = b_n + 2$

$b_{n+1} = (b_{n-1}+2) + 2 = b_{n-1} + 2\times2$

$b_{n+1} = (b_{n-2}+2) + 2\times2 = b_{n-2} + 3\times2$

and so on down to

$b_{n+1} = b_1 + 2n \implies b_{n+1} = 2n + 4 \implies b_n = 2(n-1)+4 = 2(n + 1)$

We solve for $a_n$ in the same way.

$2(n+1) = a_{n+1} - a_n \implies a_{n+1} = a_n + 2(n + 1)$

Then

$a_{n+1} = (a_{n-1} + 2n) + 2(n+1) \\ ~~~~~~~= a_{n-1} + 2 ((n+1) + n)$

$a_{n+1} = (a_{n-2} + 2(n-1)) + 2((n+1)+n) \\ ~~~~~~~ = a_{n-2} + 2 ((n+1) + n + (n-1))$

$a_{n+1} = (a_{n-3} + 2(n-2)) + 2((n+1)+n+(n-1)) \\ ~~~~~~~= a_{n-3} + 2 ((n+1) + n + (n-1) + (n-2))$

and so on down to

$a_{n+1} = a_1 + 2 \displaystyle \sum_{k=2}^{n+1} k = 2 + 2 \times \frac{n(n+3)}2$

$\implies a_{n+1} = n^2 + 3n + 2 \implies \boxed{a_n = n^2 + n}$

6 0

2 years ago

Can I get help with this question?

juin [17]

Answer:

h well jskkkskwlejsjnekekwpwkqiwjeuehwiwnwoqmwlkwkwke just trying to get pinots. sorry

7 0

2 years ago

Read 2 more answers