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otez555 [7]
3 years ago
5

What is 3 to the second power?

Mathematics
2 answers:
Nimfa-mama [501]3 years ago
5 0
3 to the second power = 3^2

3^2 = 3 x 3

3 x 3 = 9

9 is your answer

hope this helps
Alexxandr [17]3 years ago
5 0
It would be 9 because 3*3=9
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KIM [24]

The area of the sector rounded to 4 decimal place is 78.6396 cm²

<h3 /><h3>How to find the area of a sector?</h3>

area of sector = ∅/ 360 × πr²

Therefore,

  • r  = radius
  • ∅ = 46 degrees.

Hence,

area of a sector = 46 / 360 × 3.14 × 14²

area of a sector = 46 / 360 × 3.14 × 196

area of a sector =   46 / 360 × 615.44

area of a sector =   28310.24 / 360

area of a sector = 78.6395555556

Hence,

area of a sector = 78.6396 cm²

learn more on sector here: brainly.com/question/27946869

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6 0
2 years ago
The table represents the height of a ball thrown up from the roof of a building, h(t), in meters, t seconds after it is thrown u
Wittaler [7]
The answer would be b
5 0
3 years ago
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What is the value of the expression<br> below when x = 10?<br> 4x + 5<br> 8r +5
GarryVolchara [31]
There no solution sorry man
8 0
3 years ago
Please help, i need to raise my grade
Dmitrij [34]

Answer:

r=\dfrac{v^2}{a}

Step-by-step explanation:

To isolate r, we're going to need to do some algebraic manipulation.

a=\dfrac{v^2}{r}

Multiply both sides by r:

a\cdot r=v^2

Divide both sides by a:

r=\dfrac{v^2}{a}

Hope this helps!

5 0
3 years ago
A 2.2 kg ball strikes a wall with a velocity of 7.4 m/s to the left. The ball bounces off with a velocity of 6.2 m/s to the righ
Naya [18.7K]

Answer:

The constant force exerted on the ball by the wall is 119.68 N.

Step-by-step explanation:

Consider the provided information.

It is given that the mass of the ball is m = 2.2 kg

The initial velocity of the ball towards left is 7.4 m/s

So the momentum of the ball when it strikes is = 2.2\times 7.4=16.28

The final velocity of the ball is -6.2 m/s

So the momentum of the ball when it strikes back is = 2.2\times -6.2=-13.64

Thus change in moment is: 16.28-(-13.64)=29.92

The duration of force exerted on the ball t = 0.25 s

Therefore, the constant force exerted on the ball by the wall is:

\frac{29.92}{0.25}=119.68

Hence, the constant force exerted on the ball by the wall is 119.68 N.

6 0
3 years ago
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