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otez555 [7]
3 years ago
5

What is 3 to the second power?

Mathematics
2 answers:
Nimfa-mama [501]3 years ago
5 0
3 to the second power = 3^2

3^2 = 3 x 3

3 x 3 = 9

9 is your answer

hope this helps
Alexxandr [17]3 years ago
5 0
It would be 9 because 3*3=9
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In ΔHIJ, the measure of ∠J=90°, IJ = 3.2 feet, and JH = 9.6 feet. Find the measure of ∠H to the nearest tenth of a degree.
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Step-by-step explanation:

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Please help! i'm not really good at these, thank u sm if u help!
Archy [21]

Answer:

Correct: a, b, c, d, f, g, h, i, l

Incorrect: e, j, k

Step-by-step explanation:

a. -120=60(-2) {insert x and y into the equation and see if it works} Correct

b. 60 is being multiplied by hours, so it is the mph Correct

c. 60 is always the one being multiplied, so it's the constant Correct

d. 210=60(3.5) {insert 3.5 as x [cause hours] and see if it equals 210 [it does]} Correct

e. y is the dependent variable, and it represent miles driven Incorrect

f. Direct variation equation is y=kx {in the equation, k=60} Correct

g. x is the independent variable, and it represents the hours driven Correct

h. The x and the y are proportional Correct

i. y is the dependent variable, and it represent miles driven Correct

j.  y is the dependent variable, and it represent miles driven Incorrect

k. Rise=y Run=x The first point would be (1,60) {rise=60 run=1} Incorrect

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(hope this helps :P)

8 0
3 years ago
The average score of all golfers for a particular course has a mean of 71 and a standard deviation of 3. Suppose 36 golfers play
Zielflug [23.3K]

Answer:

.0228

Step-by-step explanation:

To solve this question, we need to understand the normal probability distribution and the central limit theorem.

Normal probability distribution

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

Central Limit Theorem

The Central Limit Theorem estabilishes that, for a normally distributed random variable X, with mean \mu and standard deviation \sigma, the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean \mu and standard deviation s = \frac{\sigma}{\sqrt{n}}.

For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.

In this problem, we have that:

\mu = 71, \sigma = 3, n = 36, s = \frac{3}{\sqrt{36}} = 0.5

Find the probability that the average score of the 36 golfers exceeded 72.

This is 1 subtracted by the pvalue of Z when X = 72. So

Z = \frac{X - \mu}{\sigma}

By the Central Limit Theorem

Z = \frac{X - \mu}{s}

Z = \frac{72 - 71}{0.5}

Z = 2

Z = 2 has a pvalue of 0.9772

1 - 0.9772 = 0.0228

7 0
3 years ago
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