Answer:
a) 8π
b) 8/3 π
c) 32/5 π
d) 176/15 π
Step-by-step explanation:
Given lines : y = √x, y = 2, x = 0.
<u>a) The x-axis </u>
using the shell method
y = √x = , x = y^2
h = y^2 , p = y
vol = ( 2π ) 
=
∴ Vol = 8π
<u>b) The line y = 2 ( using the shell method )</u>
p = 2 - y
h = y^2
vol = ( 2π )
= 
= ( 2π ) * [ 2/3 * y^3 - y^4 / 4 ] ²₀
∴ Vol = 8/3 π
<u>c) The y-axis ( using shell method )</u>
h = 2-y = h = 2 - √x
p = x
vol = 
= 
= ( 2π ) [x^2 - 2/5*x^5/2 ]⁴₀
vol = ( 2π ) ( 16/5 ) = 32/5 π
<u>d) The line x = -1 (using shell method )</u>
p = 1 + x
h = 2√x
vol = 
Hence vol = 176/15 π
attached below is the graphical representation of P and h
Answer:
Part 1) 
Part 2) 
Step-by-step explanation:
we have

The cos(A) is negative, that means that the angle A in the triangle ABC is an obtuse angle and the value of the sin(A) is positive
The angle A lie on the II Quadrant
step 1
Find the measure of angle A

using a calculator

step 2
Find the sin(A)
we know that

substitute the value of cos(A)




step 3
Find tan(A)
we know that

substitute the values

Simplify

Answer:
1) C. (3, 5)
2) B. Counterclockwise turn 90 degrees about the origin
3) A. C' (0, -2)
Step-by-step explanation:
i got u bro