Question

Find the number of real number solutions for the equation x^2-6=0

Answer 1

Answer:

Step-by-step explanation:

x^2-6=0

x^+6=0 ( add six to both sides)

x^2=6

x= the square root of 6 ( to get rid of the exponent you have to do the opposite....which is the square root)

x=2.44948974278

You may have to round if not given the exact number.

Answer 2

Answer:

$x=\sqrt{6}$ and $x=-\sqrt{6}$

Step-by-step explanation:

We have the following quadratic equation

$x^2-6=0$

To solve the equation add 6 to both sides of the equality

$x^2-6+6=6$

$x^2=6$

Now apply the square root function on both sides of the equation

$\sqrt{x^2}=\sqrt{6}$

$x=\±\sqrt{6}$

This means that the solutions are:

$x=\sqrt{6}$ and $x=-\sqrt{6}$