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swat32
2 years ago
9

Help plz the faster the better anyone :(

Mathematics
1 answer:
Leokris [45]2 years ago
4 0

Answer:

10.080229881683 yards2

Step-by-step explanation:

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Can someone tell me what to write of how i found the answer please ?!
Vlad [161]

Answer:

108

Step-by-step explanation:

4−22+135−9

=−18+135−9

=117−9

=108

5 0
3 years ago
Tell whether each statement about the fraction 5/9 is correct. Choose yes or no
lions [1.4K]

B and C are correct, A and D are incorrect

5 0
3 years ago
One angle of an isosceles triangle measures 26°. Which other angles could be in that isosceles triangle?
Julli [10]

Answer:

There are two answers, either of which would work

  • 26°, 26° and 128°
  • 26°, 77° and 77°

Method:

An isosceles triangle has 2 of the same sides so there are two possible answers:

1) 26° is one of the angles which is the same as another. 26° × 2 = 52° and since there are 180° in a triangle the other angle is 180° - 52° which is 128°. This would make the angles 26°, 26° and 128°

2) 26° is not one of the angles which is the same as another. Since there are 180° in a triangle, the other angles would both be 2 ÷ (180° - 26°) which is 77°. This would make the angless 26°, 77° and 77°

3 0
3 years ago
Hiii, I would love it if you can help me with these! I tried my best but it's really hard and I don't understand this.
AveGali [126]

Answer:

3rd Answer =Option A is the Correct Answer

Step-by-step explanation:

5 0
3 years ago
Read 2 more answers
I built a storage shed in the shape of a rectangular box on a square base. The material that I used for the base cost $4 per squ
kumpel [21]

Answer:

side of 6.124 ft and height of 3.674 ft

Step-by-step explanation:

Let's s be the side of the square base and h be the height of the rectangular box.

The base and the roof would have an area of s^2 and cost of

4s^2 + 2s^2 = 6s^2

The sides would have an area of 4sh and cost of 4sh*2.5 = 10sh

So the total cost for the material is

6s^2 + 10sh = 450

10sh = 450 - 6s^2

h = 45/s - 0.6s

The volume of the shed has the following formula

V = s^2h = s^2(45/s - 0.6s) = 45s - 0.6s^3

To find the maximum value for V, we can take its first derivative, and set it to 0

\frac{dV}{ds} = 45 - 1.2s^2 = 0

1.2s^2 = 45

s^2 = 45 / 1.2 = 37.5

s = \sqrt{37.5} = 6.124 ft

h = 45/s - 0.6s = 3.674 ft

4 0
3 years ago
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