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Y_Kistochka [10]
4 years ago
6

CHALLENGE ACTIVITY 2.9.1: Coordinate geometry. Determine the distance between points (x1, y1) and point (x2, y2), and assign the

result to point Distance. The calculation is: Ex: For points (1.0, 2.0) and (1.0, 5.0), points Distance is 3.0.
Computers and Technology
1 answer:
Burka [1]4 years ago
7 0

Answer:

<em>import java.util.Scanner;</em>

<em>public class TestClass {</em>

<em>    public static void main(String[] args) {</em>

<em>        Scanner input = new Scanner(System.in);</em>

<em>        System.out.println("Enter value for x1, x2, y1, y2");</em>

<em>        double x1 = input.nextDouble();</em>

<em>        double x2 = input.nextDouble();</em>

<em>        double y1 = input.nextDouble();</em>

<em>        double y2 = input.nextDouble();</em>

<em>        double xVal = Math.pow((x2-x1),2);</em>

<em>        double yVal = Math.pow((y2-y1),2);</em>

<em>        double distance = Math.sqrt(xVal+yVal);</em>

<em>        System.out.println(distance);</em>

<em>    }</em>

<em>}</em>

Explanation:

The code is written in Java Programming Language.

This code simply implements the formula for the distance between two points given as

distance =\sqrt{(x2-x1)^{2}+(y2-y1)^{2}  )}

The scanner class is used to prompt and receive all the variables that are declared.

Note that we used two special Java methods (Math.pow and Math.sqrt)

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Answer:

The program in C++ is as follows:

#include <iostream>

using namespace std;

int main(){

   int qty;

   float discount = 0;

   cout<<"Quantity: ";

   cin>>qty;

   int cost = qty * 100;

i f (cost > 1000) {        discount=cost * 0.10;        }

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Explanation:

This declares the quantity as integer

   int qty;

This declares and initializes discount to 0

   float discount = 0;

This prompts the user for quantity

   cout<<"Quantity: ";

This gets input for quantity

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This calculates the cost

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If cost is above 1000, a discount of 10% is calculated

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This prints the cost

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Answer:

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Answer:

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Answer:

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