Answer:
Option (4) is the correct answer.
Explanation:
In Java programming language ,array collection starts from 0 index location and ends in a size-1 index location. So to access the last elements the user needs to use a[Size-1] statement. so to modify the value of the last location of the array the user needs to use "a[size-1]= element;".
But when the user wants to add some new value to the end of the array list collection then he needs to use the statement--
a.add(element); //where add is a function, element is a value and a is a array list object.
Another option is invalid because--
- Option 1 is not the correct because "a[3]=element;" modify the value of the 3rd element of the array.
- Option 2 gives a compile-time error because add functions bracts are not closed.
- Option 3 gives the error because a[4] gives the location of the 5th element of the array but the above question says that a is defined with 4 elements.
Telecommunications is the electronic transmission of signals for communications, which enables organizations to carry out their processes and tasks through effective computer networks
Answer:
See explaination
Explanation:
Keep two iterators, i (for nuts array) and j (for bolts array).
while(i < n and j < n) {
if nuts[i] == bolts[j] {
We have a case where sizes match, output/return
}
else if nuts[i] < bolts[j] {
this means that size of nut is smaller than that of bolt and we should go to the next bigger nut, i.e., i+=1
}
else {
this means that size of bolt is smaller than that of nut and we should go to the next bigger bolt, i.e., j+=1
}
}
Since we go to each index in both the array only once, the algorithm take O(n) time.
Answer:
The answer is Lines.
Explanation:
A visible line, or object line is a thick continuous line, used to outline the visible edges or contours of an object. A hidden line, also known as a hidden object line is a medium weight line, made of short dashes about 1/8” long with 1/16”gaps, to show edges, surfaces and corners which cannot be seen.
10008 is the answer to your question
