Answer:
Explanation:
1. There can be a run out of something ex. The water cycle we could run out of water if evaporation stops happening
2. Something wont happen ex. In a shoe factory if no one is boxing the shoes the shoes don’t get boxed.
Hope this helps
E-mail B is the more appropriate workplace e-mail because it’s straightforward, polite, and professional. E-mail A was more accusatory and aggressive, and many people don’t like when they’re being yelled at or accused of something and, as a result, this person may start to dislike that coworker. However, the second e-mail was more polite and made the receiver think of them as a respectful person so that they’re happy to help them out.
5 Common Ethical Issues in the Workplace
Unethical Leadership.
Toxic Workplace Culture.
Discrimination and Harassment.
Unrealistic and Conflicting Goals.
Questionable Use of Company Technology.
Answer:
Answer to the following question is as follows;
Explanation:
A visual language may go a long way without even text or narrative. Introductory angles, action shots, and tracker shots may all be utilised to build a narrative, but you must be mindful of the storey being conveyed at all times. When it comes to video editing, it's often best to be as cautious as possible.
Answer:
hope this helps and do consider giving a brainliest to the ans if it helped.
Explanation:
//program to check if the entered grid is magic square or not
/**c++ standard libraries
*/
#include<bits/stdc++.h>
using namespace std;
/**function to check whether the entered grid is magic square or not
*/
int isMagicSquare(int arr[3][3]){
int i,j,sum=0,sum1=0,rsum,csum;
for(i=0;i<3;i++){
sum+=arr[i][i];
sum1+=arr[i][2-i];
}
if(sum!=sum1){
return 0;
}
for(i=0;i<3;i++){
rsum=0;
csum=0;
for(j=0;j<3;j++){
rsum+=arr[i][j];
csum+=arr[j][i];
}
if(sum!=rsum){
return 0;
}
if(sum!=csum){
return 0;
}
}
return 1;
}
/** main function to get user entries and
* call function
* and print output
*/
int main(){
int i,j,arr[3][3]={0};
for(i=0;i<3;i++){
for(j=0;j<3;j++){
cout<<"Enter the number for row "<<i<<" and column "<<j<<" : ";
cin>>arr[i][j];
}
}
int ret = isMagicSquare(arr);
if(ret==1){
cout<<"This is a Lo Shu magic square"<<endl;
}
else{
cout<<"This is not a Lo Shu magic square"<<endl;
}
return 0;
}