I don’t really understand this stuff. Anyone?

A study was conducted to estimate the difference in the mean salaries of elementary school teachers from two neighboring states.

umka21 [38]

Answer:

$(28900-30300) -2.07 \sqrt{\frac{2300^2}{10} +\frac{2100^2}{14}} = -3301.70$

$(28900-30300) +2.07 \sqrt{\frac{2300^2}{10} +\frac{2100^2}{14}} = 501.698$

The confidence interval would be $-3301.70 \leq \mu \leq 501.698$ and since the confidence interval contains the value of 0 we don't have enough evidence to conclude that the difference between the two states for the salary of teachers are significantly different.

Step-by-step explanation:

We have the following info given by the problem

$\bar X_1 = 28900$ the sample mean for the salaries of teachers in Indiana

$s_1 = 2300$ the sample deviation for the salary of teachers in Indiana

$n_1 =10$ the sample size from Indiana

$\bar X_2 = 30300$ the sample mean for the salaries of teachers in Michigan

$s_2 = 2100$ the sample deviation for the salary of teachers in Michigan

$n_2 =14$ the sample size from Michigan

We want to find a confidence interval for the difference in the two means and the formula for this case is given by;

$(\bar X_1 -\bar X_2) \pm t_{\alpha/2}\sqrt{\frac{s^2_1}{n_1} +\frac{s^2_2}{n_2}}$

The degrees of freedom for this case are:

$df = n_1 +n_2 -2= 10+14-2 =22$

The confidence is 95%so then the significance is $\alpha=0.05$ and the $\alpha/2 =0.025$ , we need to find a critical value in the t distribution with 22 degrees of freedom who accumulates 0.025 of the area on each tail and we got:

$t_{\alpha/2}= 2.07$

And now replacing in the formula for the confidence interval we got:

$(28900-30300) -2.07 \sqrt{\frac{2300^2}{10} +\frac{2100^2}{14}} = -3301.70$

$(28900-30300) +2.07 \sqrt{\frac{2300^2}{10} +\frac{2100^2}{14}} = 501.698$

The confidence interval would be $-3301.70 \leq \mu \leq 501.698$ and since the confidence interval contains the value of 0 we don't have enough evidence to conclude that the difference between the two states for the salary of teachers are significantly different.

6 0

3 years ago

How do you Solve 2|x|=3

HACTEHA [7]

If yo have |a|=b solve for a such that a=b or a=-b
divideboth sides by 2

|x|=3/2

x=3/2 or -3/2

8 0

3 years ago

What is the midpoint of line segment AB

astra-53 [7]

I believe that it is E since it is pretty obvious where the middle is you just do rise/run which gives you 2,-1

3 0

3 years ago

The equation is 2(4x-11)=10 and how do you divide each side of the equation by 2.

Ierofanga [76]

Answer:

4x-11=5

Step-by-step explanation:

If u were to divide each side of the equation by 2, the 2 on the left which is supposed to distribute into the parenthesis would disappear, and the 10 on the right side would turn into 5.

What is left is this,

4x-11=5

7 0

3 years ago

HELP AGAIN :))) PLEASE HELP

Zielflug [23.3K]

Answer:

55

Step-by-step explanation:

This is 55 because you need to make a sum of 180 when making a line and 125+55=180

4 0

3 years ago

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