Answer:
The probability that a randomly chosen code starts with M and ends with E is 0.05 ....
Step-by-step explanation:
According to the given statement we have to make five letter code from A, F, E, R, and M without repeating any letter. We have to find that what is probability that a randomly chosen code starts with M and ends with E.
Thus the probability of picking the first letter M = 1/5
After that we require the sequence (not E, not E, not E) which is equal to:
= 3/4 * 2/3* *1/2
= 1/4
Now multiply 1/5 and 1/4
1/5 * 1/4
= 1/20
= 0.05
Therefore the probability that a randomly chosen code starts with M and ends with E is 0.05 ....
2t + 4 < -8
2t < -12
t < -6
For the inequality to be true, t must be a number that is less than -6.
Hope this helps!
Answer:
if there were 8 cats then theres 8 cats, or 32 dogs
Step-by-step explanation:
Answer:
y=-4x+5
Step-by-step explanation:
the line goes down 4 for every 1 that x changes. the line crosses the y axis at 5.
(this might not be accurate, I can't really see if the line is on the exact point or not)
Answer:
x=27.8
Step-by-step explanation:
first, you need to find y. 2y-5=65. 65+5 is 60 and you are left with 2y=70. to get the 2 off of the y you divide everything by 2. 70/2 is 35 therefor y=35. Now you plug that into the other equation (2x+y) and get 2x+35 which is equal to segment 90.6 so 2x+35=90.6. subtract 35 on both sides and you have 2x=55.6. To get the 2 off the x, we divide everything by 2. all of that divided by 2 is x=27.8
