Question

If 32*937 is divisible by 3 , which smallest digit can be replaced in * place ?​

Answer 1

We know the divisibility rule for 3

• If sum of digits is divisible by 3 then the number is divisible by 3

Find sum of dusit excluding *

$\\ \sf\longmapsto 3+2+9+3+7=24$

• 24 is divisible by 3
• Hence *=0

Answer 2

SOLUTION:

we can find the missing number by firstly finding the sum of digits of the given numbers and then subtract it from those multiple of 3, which are greater than this sum to get the smallest and greatest digits.

i) 6+7+2+4=19

multiples of 3 greater than 19 are 21,22,27,30

therefore, 21-19=2, 24-19=5, 27-19=8, 30-19=11

smallest digit=2 greatest digit=8

ii) 4+7+6+5+2=24

24 is a multiple of 3 so smallest digit is 0 greater than 24 are 27,30,33,36

27-24=3, 30-24=6, 33-24=9 36-24=12

smallest digit=0 and greatest digit=9