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liraira [26]
3 years ago
9

Can someone help me with a few easy math questions?

Mathematics
2 answers:
saw5 [17]3 years ago
8 0
Sure what kind of questions are they??
hodyreva [135]3 years ago
3 0
1+1
1+2
1+3
1+4
1+5
1+6
1+7
1+8
1+9
1+10
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Brennan has already run 16 miles on his own, and he expects to run 3 miles during each track practice. How many track practices
pentagon [3]

Answer:

It would take Brennan 4 track practice runs.

Step-by-step explanation:

He has already run 16 miles and needs to run 28 in total. If we are counting the 16 in the 28 miles, he would need to run only 12 more to reach his goal. And if he runs 3 miles a run, it would take him about 4 runs to finish his 28-mile goal.

(28-16=12 and 12/3=4)

8 0
3 years ago
Read 2 more answers
Graph the function f(x)= 2x -4
galben [10]
The y intercept and -4 and going down 2 and 1 right u til you reach the end of the graph
7 0
1 year ago
david took 10 1/2 hours over 3 days to build airplane. he spent 3 1/4 hrs the firsr day and 4 2/3 hours the second day. how many
Anuta_ua [19.1K]
2 7/12 hours

X=101/2 - ( 3+4+1/4+2/3)

X=101/2 - 7 + (1/4+2/3)

1/4+2/3= 11/12

101/2 - 7 =3 1/5

X = 3 1/5 - 11/12 = 2 7/12
8 0
3 years ago
Any one know geometry please help me out
MA_775_DIABLO [31]

Answer:

X = 4

Step-by-step explanation:

And then the nearest tenth would be 0

cause all numbers that have 4 round to like 0 or the tenth under it. If it has a five or higher it rounds to 10 or the number above it

7 0
2 years ago
Read 2 more answers
A geologist has collected 5 specimens of basaltic rock and 7 specimens of granite. The geologist instructs a laboratory assistan
MaRussiya [10]

The rocks are chosen without replacement, which means that the hypergeometric distribution is used to solve this question. First we get the parameters, and then we answer the questions. From this, we get that:

  • E(X) = 5.25, Var(X) = 0.5966
  • P(X < 6) = 0.9545
  • P(all specimens of one of the two types of rock are selected for analysis) = 0.2046.

Hypergeometric distribution:

The probability of x successes is given by the following formula:

P(X = x) = h(x,N,n,k) = \frac{C_{k,x}*C_{N-k,n-x}}{C_{N,n}}

In which:

x is the number of successes.

N is the size of the population.

n is the size of the sample.

k is the total number of desired outcomes.

Combinations formula:

C_{n,x} is the number of different combinations of x objects from a set of n elements, given by the following formula.

C_{n,x} = \frac{n!}{x!(n-x)!}

The mean and the variance are:

\mu = \frac{nk}{N}

\sigma^2 = \frac{nk(N-k)(N-n)}{N^2(N-1)}

We have that:

5 + 7 = 12 rocks, which means that N = 12

9 are chosen, which means that n = 9

7 are granite, which means that k = 7

Question a:

E(X) = \mu = \frac{9\times7}{12} = 5.25

Var(X) = \sigma^2 = \frac{9\times7(12-7)(12-9)}{12^2(12-1)} = 0.5966

Thus:

E(X) = 5.25, Var(X) = 0.5966

Question b:

Since there are only 5 specimens of basaltic rock, at least 9 - 5 = 4 specimens of granite are needed, which means that:

P(X < 6) = P(X = 4) + P(X = 5) + P(X = 6)

In which

P(X = x) = h(x,N,n,k) = \frac{C_{k,x}*C_{N-k,n-x}}{C_{N,n}}

P(X = 4) = h(4,12,9,7) = \frac{C_{7,4}*C_{5,5}}{C_{12,9}} = 0.1591

P(X = 5) = h(5,12,9,7) = \frac{C_{7,5}*C_{5,4}}{C_{12,9}} = 0.4773

P(X = 6) = h(6,12,9,7) = \frac{C_{7,6}*C_{5,3}}{C_{12,9}} = 0.3181

Thus

P(X < 6) = P(X = 4) + P(X = 5) + P(X = 6) = 0.1591 + 0.4773 + 0.3181 = 0.9545

So P(X < 6) = 0.9545.

Question c:

5 of basaltic and 4 of granite: 0.1591 probability.

7 of granite is P(X = 7), in which

P(X = 7) = h(7,12,9,7) = \frac{C_{7,7}*C_{5,2}}{C_{12,9}} = 0.0455

0.1591 + 0.0455 = 0.2046, thus:

P(all specimens of one of the two types of rock are selected for analysis) = 0.2046.

A similar question is found at brainly.com/question/24008577

5 0
3 years ago
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