In ΔPQR, the measure of ∠R=90°, RQ = 16, PR = 63, and QP = 65. What ratio represents the cosine of ∠Q?
1 answer:
Answer:
Cos Q = 16/65
Step-by-step explanation:
In this question, we have a triangle and we have the information above supplied. We are being tasked with getting the ratio of the cosine.
To do this, we shall be making reference to a diagrammatic representation of the information supplied. Please do check the attachment section for this.
Looking at this triangle, we can see that one of the angles measure 90, what this means is that what we are dealing with is a right-angled triangle.
Now to get the answer in the question, we have to define what is meant by the cosine. The cosine is a trigonometric ratio of the adjacent to the hypotenuse.
In this case, our adjacent is 16 while our hypotenuse is the longest side which is 65.
Hence, Cos Q = 16/65
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Answer:
(a) 0.119
(b) 0.1699
Solution:
As per the question:
Mean of the emission, million ponds/day
Standard deviation, million ponds/day
Now,
(a) The probability for the water pollution to be at least 15 million pounds/day:
= 1 - P(Z < 1.178)
Using the Z score table:
= 1 - 0.881 = 0.119
The required probability is 0.119
(b) The probability when the water pollution is in between 6.2 and 9.3 million pounds/day:
P(Z < - 0.86) - P(Z < - 1.96)
Now, using teh Z score table:
0.1949 - 0.025 = 0.1699