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GaryK [48]
3 years ago
8

In ΔPQR, the measure of ∠R=90°, RQ = 16, PR = 63, and QP = 65. What ratio represents the cosine of ∠Q?

Mathematics
1 answer:
expeople1 [14]3 years ago
7 0

Answer:

Cos Q = 16/65

Step-by-step explanation:

In this question, we have a triangle and we have the information above supplied. We are being tasked with getting the ratio of the cosine.

To do this, we shall be making reference to a diagrammatic representation of the information supplied. Please do check the attachment section for this.

Looking at this triangle, we can see that one of the angles measure 90, what this means is that what we are dealing with is a right-angled triangle.

Now to get the answer in the question, we have to define what is meant by the cosine. The cosine is a trigonometric ratio of the adjacent to the hypotenuse.

In this case, our adjacent is 16 while our hypotenuse is the longest side which is 65.

Hence, Cos Q = 16/65

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The travel time on a section of a Long Island Expressway (LIE) is normally distributed with a mean of 80 seconds and a standard
user100 [1]

Answer:

The travel time that separates the top 2.5% of the travel times from the rest is of 91.76 seconds.

Step-by-step explanation:

Normal Probability Distribution

Problems of normal distributions can be solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the z-score of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.

Mean of 80 seconds and a standard deviation of 6 seconds.

This means that \mu = 80, \sigma = 6

What travel time separates the top 2.5% of the travel times from the rest?

This is the 100 - 2.5 = 97.5th percentile, which is X when Z has a p-value of 0.975, so X when Z = 1.96.

Z = \frac{X - \mu}{\sigma}

1.96 = \frac{X - 80}{6}

X - 80 = 6*1.96

X = 91.76

The travel time that separates the top 2.5% of the travel times from the rest is of 91.76 seconds.

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3 years ago
What is the original price:$65.00; Markdown: 12%
alexandr1967 [171]
The answer to this question is $57.02
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3 years ago
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