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enot [183]
4 years ago
15

O is the center of the circle. Assume that lines that appear to be tangent are tangent. What is the value of x?

Mathematics
2 answers:
andrew11 [14]4 years ago
7 0
Given that QO is the radius and PQ is tangent to circle O, then ΔPQO is a right triangle. Hence the value of x will be obtained as follows:
Sum of angles in a triangle is equal to 180°. Thus
x+17+90=180
x+107=180
thus
x=180-107
x=73°

Answer: x=73°
faltersainse [42]4 years ago
5 0
The answer is 78................................
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Write 100,000 as a power of 10. A) 103 B) 104 C) 105 D) 106
mamaluj [8]
 A)10^3 = 10 * 10 * 10 = 1,000
It is not A

B)10^4 = 10 * 10 * 10 * 10 = 10,000
It is not B

C)10^5 = 10 * 10 * 10 * 10 * 10 = 100,000
It could be C

D)10^6 = 10 * 10 * 10 * 10 * 10 * 10 = 1,000,000
It is not D

Your answer is C)10^5

Hope I helped!
3 0
4 years ago
A patient is to receive 2.6 grams of medication. The medication is available in capsules of 325 milligrams. How many capsules sh
sesenic [268]
2.6 gr = 2,600 mgr
2,600 mgr /325=8
Answer is 8 capsules
8 0
3 years ago
sured 25earthworms in each container and recorded their lengths inmillimeters. Here are histograms of the lengths for each conta
irina1246 [14]

We will have to find the best option that has a wide wider range of 15 milimeters.

From the images given,

Option A will not be suitable because most of the worms tend towards 30 and 50

Option B is most suitable because most of the worm fall reasonably within this range

4 0
1 year ago
Evaluate f(x)= 1.8 X 2^x for x=6 <br><br> A: 115.2<br><br> B: 2176.78<br><br> C: 21.6
attashe74 [19]
By substitution
f(6) = 1.8×2^(6)
= 1.8×64
= 115.2
3 0
3 years ago
Read 2 more answers
A local business has an area reserved behind the store for a parking lot that is 78 meters long by 19 meters wide. The stalls of
S_A_V [24]

The total area available for cars to park will be 858m².

<h3>How to calculate the area?</h3>

The area of the parking lot will be:

= 78 × 19

= 1482m²

The area of aisle will be:

= 8 × 78

= 624m²

The available area will be:

= 1482m² - 624m²

= 858m².

The compact parking spaces that will fit in the lot will be:

N × 12.5 = 858

N = 858/12.5

N = 68

The non compact parking spaces that will fit in the lot will be:

N × 16.5 = 858

N = 858/16.5

N = 52

Learn more about area on:

brainly.com/question/7438648

#SPJ1

5 0
2 years ago
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