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Masteriza [31]
3 years ago
6

the volume of a sphere is a function of its radius. find the volume of air in a standard volleyball with a diameter of 8.5 inche

s, given v=4/3πr^3
Mathematics
1 answer:
alekssr [168]3 years ago
7 0

Answer:

The volume of air in a standard volleyball of diameter 8.5 inches is 321.68 inches^3

Step-by-step explanation:

Here, we want to calculate the volume of air in a standard volleyball.

Mathematically, in this case, we know that the air will fill up the entire mass of the volleyball.

So, by calculating the volume of the volleyball, we have successfully calculated the volume of air.

Mathematically, from the question, we already have the formula to use

v=4/3πr^3

Where π = 22/7

r = diameter/2 = 8.5/2 = 4.25 inches

Substituting these values into the volume equation, we have;

V = 4/3 * 22/7 * 4.25^3 = 321.68 inches^3

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photoshop1234 [79]
The slope intercept IS y=2/5x+7
5 0
3 years ago
You believe that eating an apple a day is healthy and want to design an experiment to find out. You have available 40 volunteers
Gwar [14]

The best design for this experiment would be a repeated measures design. This is ideal to determine if eating an apple makes you healthy.

<h3>What is an experimental design?</h3>

An experimental design refers to the general structure of an experiment including how people are distributed into the control and experimental group to test a specific phenomenon.

<h3>What is a repeated measures design?</h3>

In a repeated measures design all participants are both parts of the control group, in this case, people who do not eat apples, and the experimental group, or people who eat apples.

<h3>What does this design imply?</h3>

In the case of determining if eating an apple every day, this design implies:

  • All participants will be asked to not eat apples every day for a specific period such as one or two months, and health levels will be measured during this time.
  • After the first step, all participants will be asked to eat an apple every day during the period, and their health will be measured.
  • The researcher can compare the results of each participant, which is more accurate than comparing one participant to another.

Learn more about experiments in: brainly.com/question/1452319

7 0
2 years ago
Customers arrive at a movie theater at the advertised movie time only to find that they have to sit through several previews and
sergij07 [2.7K]

Answer:

a) sample size is 40

Step-by-step explanation:

(a)

\sigma=4 minutes

Margin of error, E is 75 seconds E=75/60= 1.25 minutes.

The level of significance \alpha= 0.05 for 95% level of significance

For 95% confidence interval z_{\frac{\alpha}{2}}=1.96 from standard deviation table

Sample size required, n

n=\left (\frac{z_{\frac{\alpha}{2}}\cdot \sigma}{E} \right )^{2}=\left (\frac{1.96\cdot4}{75/60} \right )^{2}=39.337984

Rounding off, n=40

Sample size =40

Keywords:

95% confidence, sample size, Wall Street Journal

3 0
3 years ago
Needdd hellpppppssssssss
Ratling [72]

Answer:

Choice number one:

\displaystyle \frac{5}{10}\cdot \frac{4}{9}.

Step-by-step explanation:

  • Let A be the event that the number on the first card is even.
  • Let B be the event that the number on the second card is even.

The question is asking for the possibility that event A and B happen at the same time. However, whether A occurs or not will influence the probability of B. In other words, A and B are not independent. The probability that both A and B occur needs to be found as the product of

  • the probability that event A occurs, and
  • the probability that event B occurs given that event A occurs.

5 out of the ten numbers are even. The probability that event A occurs is:

\displaystyle P(A) = \frac{5}{10}.

In case A occurs, there will only be four cards with even numbers out of the nine cards that are still in the bag. The conditional probability of getting a second card with an even number on it, given that the first card is even, will be:

\displaystyle P(B|A) = \frac{4}{9}.

The probability that both A and B occurs will be:

\displaystyle P(A \cap B) = P(B\cap A) =  P(A) \cdot P(B|A) = \frac{5}{10}\cdot \frac{4}{9}.

6 0
3 years ago
Solve for x 6-12x = -54
kvasek [131]

Answer:

The answer of the question is 5

8 0
3 years ago
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