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Masteriza [31]
3 years ago
6

the volume of a sphere is a function of its radius. find the volume of air in a standard volleyball with a diameter of 8.5 inche

s, given v=4/3πr^3
Mathematics
1 answer:
alekssr [168]3 years ago
7 0

Answer:

The volume of air in a standard volleyball of diameter 8.5 inches is 321.68 inches^3

Step-by-step explanation:

Here, we want to calculate the volume of air in a standard volleyball.

Mathematically, in this case, we know that the air will fill up the entire mass of the volleyball.

So, by calculating the volume of the volleyball, we have successfully calculated the volume of air.

Mathematically, from the question, we already have the formula to use

v=4/3πr^3

Where π = 22/7

r = diameter/2 = 8.5/2 = 4.25 inches

Substituting these values into the volume equation, we have;

V = 4/3 * 22/7 * 4.25^3 = 321.68 inches^3

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garik1379 [7]

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Step-by-step explanation:

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_____

<em>Comment on the question and answer</em>

Your description "on the circle between points Q and N" is ambiguous. You used the same description for both points P and R. The interpretation we used is shown in the attachment. If point P is on the long arc NQ, then the measure of arc QPN will be the difference between 148° and 360°, hence 212°. You need to choose the answer that matches the diagram you have.

__

We call angle QNT an "inscribed angle" because it is a degenerate case of an inscribed angle. The usual case has the vertex of the angle separate from the ends of the arc it intercepts. In the case of a tangent meeting a chord, the vertex is coincident with one of the ends of the intercepted arc. The relation between angle measure and arc measure remains the same: 1 : 2.

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