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Setler79 [48]
2 years ago
5

Can u help me solve this pls

Mathematics
2 answers:
9966 [12]2 years ago
6 0

Answer:

2x +3(x +1.5)=12

Step-by-step explanation:

you do this because you are trying to find what x equals,

BTW I’m doing this right now as well

lisov135 [29]2 years ago
3 0
Answer:

First option: (Substitute)

2x+3 (x+1.5) = 12
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What is 50 times 50<br> i realy need help on this and plz help me on this
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50*50 is 2,500

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Can Someone Please Help Me With This Question. I'll post a picture of the question ​
Vedmedyk [2.9K]

Answer:

y-7=3(x-9)

Step-by-step explanation:

The form of equation of line given in the problem is the point-slope form of a line. That is given by:

y-y_1=m(x-x_1)

We need y_1 and m (denoted by boxes)

y_1 is the y coordinate of the first set of points.

The first coordinate pair is (9,7), so y_1  would be 7

y_1=7

Now, the slope (m).

It has formula

m=\frac{y_2-y_1}{x_2-x_1}

So, x_1 = 9

y_1 = 7

x_2 = 4

y_2 = -8

Substituting, we get the slope to be:

m=\frac{y_2-y_1}{x_2-x_1}\\m=\frac{-8-7}{4-9}\\m=\frac{-15}{-5}\\m=3

Hence, the equation of the line in point-slope is:

y-7=3(x-9)

5 0
2 years ago
Find the value of x and the length of both chords if BW=2x+10, WD=4, CW=7x+5, and WE=2.
daser333 [38]

Answer:

The value of x is 5

The lengths of the chords are 24 units and 42 units

Step-by-step explanation:

In a circle if two chords intersected at a point inside it there are four segments created, two in each cord, the products of the lengths of the line segments on each chord are equal

∵ BD and CE are two chords in a circle intersected at W

∴ The two segments of chord BD are BW and WD

∴ The two segments of chord CE are CW and WE

- By using the rule above

∴ BW × WD = CW × WE

∵ BW = 2x + 10 and WD = 4

∵ CW = 7x + 5 and WE = 2

- Substitute them in the rule above

∴ (2x + 10) × 4 = (7x + 5) × 2

∴ 4(2x) + 4(10) = 2(7x) + 2(5)

∴ 8x + 40 = 14x + 10

- Subtract 14x from both sides

∴ - 6x + 40 = 10

- Subtract 40 from both sides

∴ - 6x = - 30

- Divide both sides by - 6

∴ x = 5

∵ Chord BD = 2x + 10 + 4

∴ Chord BD = 2x + 14

- Substitute the value of x to find its length

∴ Chord BD = 2(5) + 14 = 10 + 14

∴ Chord BD = 24 units

∵ Chord CE = 7x + 5 + 2

∴ Chord CE = 7x + 7

- Substitute the value of x to find its length

∴ Chord CE = 7(5) + 7 = 35 + 7

∴ Chord CE = 42 units

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2 years ago
Write the equation of each ellipse in standard form with the given characteristics.
Eddi Din [679]

Answer:

Step-by-step explanation:

The foci are horizontally aligned.

horizontal ellipse:

(x-h)²/a² + (y-k)²/b² = 1

center (h,k)

vertices (h±a,k)

length of minor axis = 2b

foci (h±c,k), c² = a²-b²

Apply your data and solve for h, k, a, and b.

foci (±3√19, 6)

h = 0

k = 6

Length of minor axis = 2b = 10

b = 5

foci (h±3√19, 6)

c = 3√19

c³ = a² - b²

171 = a² - 25

a²  = 196

x²/196 + (y-6)²/25 = 1

6 0
2 years ago
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