Answer:
Using C++ to solve the problem as given below
Explanation:
#include<iostream>
#include<string.h>
using namespace std;
int main()
{
string salsa_name[5]={"mild","medium","sweet","hot","zesty"};
int jar_sale[5]={0,0,0,0,0};
int i;
int total=0;
int high=0;
int high_index=0;
int low=0;
int low_index=0;
int temp=0;
for(i=0;i<5;i++)
{
while(temp<=0)
{
cout<<"enter the number of jars sold for "<<salsa_name[i]<<" ";
cin>>temp;
if(temp<=0)
cout<<"invalid data. please try again\n";
}
jar_sale[i]=temp;
temp=0;
}
cout<<"name\t jars sold\n";
cout<<"\n---------------------------\n";
for(i=0;i<5;i++)
{
cout<<" "<<salsa_name[i]<<"\t\t"<<jar_sale[i]<<"\n";
}
low=jar_sale[0];
for(i=0;i<5;i++)
{
total=total+jar_sale[i];
if(jar_sale[i] >= high)
{
high_index=i;
high=jar_sale[i];
}
if(jar_sale[i]<=low)
{
low_index=i;
low=jar_sale[i];
}
}
cout<<"\n total sale : "<<total;
cout<<"\n high seller : "<<salsa_name[high_index];
cout<<"\n low seller : "<<salsa_name[low_index];
}
I was unable to click on any of my notifications but that got fixed on its own a day later.
Answer:
Tell her about cyber bullies
Tell her about hackers
stalkers
identity theft
spam
Sorry if wrong
Explanation:
Answer:
To check if the year comes under each 100th year, lets check if the remainder when dividing with 100 is 0 or not.
Similarly check for 400th year and multiple 0f 4. The following C program describes the function.
#include<stdio.h>
#include<stdbool.h>
bool is_leap_year(int year);
void main()
{
int y;
bool b;
printf("Enter the year in yyyy format: e.g. 1999 \n");
scanf("%d", &y); // taking the input year in yyyy format.
b= is_leap_year(y); //calling the function and returning the output to b
if(b==true)
{
printf("Thae given year is a leap year \n");
}
else
{
printf("The given year is not a leap year \n");
}
}
bool is_leap_year(int year)
{
if(year%100==0) //every 100th year
{
if(year%400==0) //every 400th year
{
return true;
}
else
{
return false;
}
}
if(year%4==0) //is a multiple of 4
{
return true;
}
else
{
return false;
}
}
Explanation:
Output is given as image