Question

Suppose the probability of producing a defective light bulb from a production line is the same over an interval of 90 minutes. Which of the following distributions would you use to determine the probability that a defective light bulb will be produced in a 15-minute interval? A) Normal distribution B) Poisson distribution C) Uniform distribution D) Exponential distribution

Answer 1

Answer:

C) Uniform distribution

Step-by-step explanation:

An uniform probability is a case of probability in which each outcome is equally as likely. In this case, the probability of producing a defective light bulb from a production line is the same over an interval of 90 minutes, so the correct answer is C.

We can calculate the probability.

Uniform probability distribution

For this situation, we have a lower limit of the distribution that we call a and an upper limit that we call b.

The probability that we find a value X lower than x is given by the following formula.

$P(X \leq x) = \frac{x - a}{b-a}$

For this problem, we have that:

Uniformily distributed over a 90 minute interval, that is, between 0 and 90, so $b = 90$ and $a = 0$.

We want to find $P(X \leq 15) = \frac{15-0}{90-0} = 0.167$