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3 years ago

GEOMETRY HELP PLEASEEEEEEE!!

Mathematics

1 answer:

Nadya [2.5K]3 years ago

3 0

For number 11 the third angle would be equal X as the second angle is, since the two sides next to the those angles are congruent. Then you would have to set an equation saying that 2x + 38= 180 and then you can just solve for X

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7. Are the two lines parallel, perpendicular, or neither? Explain your answer. Show work needed to answer the

kiruha [24]

Answer:

The lines are perpendicular

Step-by-step explanation:

5 0

2 years ago

Draw an example of a composite figure that has a volume between 750 cubic inches and 900 cubic inches

grigory [225]

Volume:

$V \approx 888.02in^3 \\ \\ And, \ 750in^3$

<h2>Explanation:</h2>

A composite figure is formed by two or more basic figures or shapes. In this problem, we have a composite figure formed by a cylinder and a hemisphere as shown in the figure below, so the volume of this shape as a whole is the sum of the volume of the cylinder and the hemisphere:

$V_{total}=V_{cylinder}+V_{hemisphere} \\ \\ \\ V_{total}=V \\ \\ V_{cylinder}=V_{c} \\ \\ V_{hemisphere}=V_{h}$

So:

$V_{c}=\pi r^2h \\ \\ r:radius \\ \\ h:height$

From the figure the radius of the hemisphere is the same radius of the cylinder and equals:

$r=\frac{8}{2}=4in$

And the height of the cylinder is:

$h=15in$

So:

$V_{c}=\pi r^2h \\ \\ V_{c}=\pi (4)^2(15) \\ \\ V_{c}=240\pi in^3$

The volume of a hemisphere is half the volume of a sphere, hence:

$V_{h}=\frac{1}{2}\left(\frac{4}{3} \pi r^3\right) \\ \\ V_{h}=\frac{1}{2}\left(\frac{4}{3} \pi (4)^3\right) \\ \\ V_{h}=\frac{128}{3}\pi in^3$

Finally, the volume of the composite figure is:

$V=240\pi+\frac{128}{3}\pi \\ \\ V=\frac{848}{3}\pi in^3 \\ \\ \\ V \approx 888.02in^3 \\ \\ And, \ 750in^3$

<h2>Learn more:</h2>

Volume of cone: brainly.com/question/4383003

#LearnWithBrainly

4 0

2 years ago

2 factor of 28 added up to 9

kaheart [24]

I think its 14 because in order to get to 28 but 2 you count 14 times saying 2×14

5 0

2 years ago

Tara ran the 1600 M event at a constant speed in 5 minutes and 20 seconds. what was her speed

ollegr [7]

5 m/sec or 300m / min

using speed = $\frac{distance}{time}$

change 5 min 20 sec to seconds = (5 × 60) + 20 = 320 sec

speed = $\frac{1600}{320}$ = 5m / second or

speed = 60 × 5 = 300m / minute

4 0

2 years ago

How do you increase 300 by 54%?

Vanyuwa [196]

Multiply 300 by 54%= 16,200
Divide 16,200 by 100
= 162.20
Round 162.20 to the nearest whole
= 162
hope this helps.
This is the steps to finding a percent

4 0

2 years ago