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myrzilka [38]
3 years ago
8

GEOMETRY HELP PLEASEEEEEEE!!

Mathematics
1 answer:
Nadya [2.5K]3 years ago
3 0
For number 11 the third angle would be equal X as the second angle is, since the two sides next to the those angles are congruent. Then you would have to set an equation saying that 2x + 38= 180 and then you can just solve for X
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5 0
2 years ago
Abby used the law of cosines for TriangleKMN to solve for k.
torisob [31]

Answer:

  m∠K = 37° and n = 31

Step-by-step explanation:

A lot of math is about matching patterns. Here, the two patterns we want to match are different versions of the same Law of Cosines relation:

  • a² = b² +c² -2bc·cos(A)
  • k² = 31² +53² -2·31·53·cos(37°)

<h3>Comparison</h3>

Comparing the two equations, we note these correspondences:

  • a = k
  • b = 31
  • c = 53
  • A = 37°

Comparing these values to the given information, we see that ...

  • KN = c = 53 . . . . . . . . . . matching values 53
  • NM = a = k . . . . . . . . . . . matching values k
  • KM = b = n = 31 . . . . . . . matching values 31
  • ∠K = ∠A = 37° . . . . . . . matching side/angle names

Abby apparently knew that ∠K = 37° and n = 31.

__

<em>Additional comment</em>

Side and angle naming for the Law of Sines and the Law of Cosines are as follows. The vertices of the triangle are labeled with single upper-case letters. The side opposite is labeled with the same lower-case letter, or with the two vertices at either end.

Vertex and angle K are opposite side k, also called side NM in this triangle.

5 0
2 years ago
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