Answer:
a) Khaled's backyard at his old house is 10 yards by 22 yards. You can interpret 10 by 22 as:
width (w) = 10 yards
and height (h) = 22 yards
OR
length (l) = 22 yards
width (w) = 10 yards
Generally, length are longer than width.
Thus, this is a problem of a rectangle. To find the area of the backyard at his old house. We know,
- Area of a rectangle = l × w
= 22 × 10
= 210 yards sq.
sq. is an abbreviation of squared.
From the second measurement 15 yards by 15 yards we know that, length and width are similar for the backyard at his current house. Therefore,
To find the area of the backyard at his current house. We know:
length (a) = 15 yards
Area of a square = a^2 or a × a
= 15^2 or 15 × 15
= 225 yards sq.
sq. is an abbreviation of squared.
b) By definition perimeter is length of all sides that encloses an object.
Here, Khaled has 4 sides.
Therefore, Perimeter of his old backyard= 2l + 2w
= 2 × 10 + 2× 22
= 20 + 44
= 64 yards
And Perimeter of his current backyard = 4l
= 4 × 15
= 60 yards
c) Khaled's current backyard has more area than his old backyard, thus, Khaled's kids has more room in current backyard to play in.
d)Khaled's current backyard has a perimeter of 60 yards and his old backyard has a perimeter of 64 yards. Because his old backyard needs to cover 4 extra yards than his current backyard. Khaled's old backyard will need more fences to enclose.
