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VLD [36.1K]
3 years ago
8

The graph shows the relationship between the distance a truck can travel and the amount of gasoline used. (5,35) What is the uni

t rate for the distance traveled to the amount of gasoline used? (1,7) Enter your answer in the box. mpg
Mathematics
2 answers:
juin [17]3 years ago
8 0
The unit rate is the slope

y=mx+b

m=slope

b=y intercept

equation is y=7x

slope=7

y intercept=0

slope=unit rate because if you use 5 gasoline then you go 5 times 7 miles or 35 miles

The unit rate is 7

Hope I helped :)
boyakko [2]3 years ago
6 0

Answer:

y=7x or the answer is 7

Step-by-step explanation:

i took the test in (k12)

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ZanzabumX [31]
We will use the equation 74.06-56.48=? To find the change in prices, aka how much more money was spent. That equals 17.58. So A, Michael spent $17.58 more than Denise.
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Suppose you get a cut on your finger and 5 bacteria cells get into the cut. Each hour the number of bacteria cells will double u
BlackZzzverrR [31]

Answer:

5⁶⁴ = 152587890625⁴ bacteria's at 7 hours

Step-by-step explanation:

Simple..

it means the bacteria is increasing exponentially.

This is a geometric progression.

at 0 hrs = 0 bacteria

at 1 hr = 5 bacteria

at 2hr = 25 " = 5²

at 3hrs = 25 x 25 = 5² x 5² = 5⁴

at 4hrs = (25x25) x (25x25) = 5⁴x5⁴ = 5⁸

at 5hrs = (5⁸)² = 5⁸ˣ² = 5¹⁶

at 6 hrs = (5¹⁶)² = 5¹⁶ˣ²= 5³²

at 7 hrs = (5³²)² = 5³²ˣ² = 5⁶⁴

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3 years ago
Mr. Blue drove from Allston to Brockton, a distance of 105 miles. On his way back, he increased his speed by 10 mph. If the jour
andrew-mc [135]

Answer:

His original speed was 60 mph.

Step-by-step explanation:

The average speed formula is shown below:

speed = distance / time

For the first leg of the trip Mr. Blue drove at a speed of "x" mph, for a distance of 105 miles, therefore the time that took to complete the trip is:

time 1 = distance / speed

time 1 = 105 / x h

On the second leg of the trip Mr. Blue drove faster at a speed of "x + 10" mph, so the time it took him to complete the trip was 15 minutes less, therfore:

time 2 = time1 - (15/60) = (105/x) - 0.25 = (105 - 0.25*x)/x h

Applyint the time and speed from the second leg to the average speed formula we have:

x + 10 = {105/[(105 - 0.25*x)/x]}

x + 10 = 105*x/(105 - 0.25*x)

(x + 10)*(105 - 0.25*x) = 105*x

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-0.25*x² -2.5*x + 1050 = 0 /(-0.25)

x² + 10*x - 4200 = 0

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x2 = [-(10) - sqrt((10)² - 4*(1)*(-4200))]/2 = -70

Since his speed couldn't be negative the only possible value was 60 mph.

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