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4 years ago

What is the value of x in this number sentence? 32 = 17 + x

Mathematics

2 answers:

vlada-n [284]4 years ago

3 0

32 = 17 + x
32 - 17 = x
15 = x

Temka [501]4 years ago

3 0

32 = 17 + x
To find our answer, the value of x, we only have to substract 17 from both sides. This gives us the following
15 = x
x = 15
So the value of x in this number sentence is 15

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6. David gets 65 chocolates an hour for cleaning. He gets a 15% raise. He

Sonja [21]

Answer:

Before raise: 65 chocolates/hour*60=3900 chocolates

Raise=65 * (15%=15/100=.15) .15=9.75 more chocolates per hour

With raise 74.75 chocolates/hour*60=4485 chocolates

4485-3900=585 more chocolates per 60 hour week

Step-by-step explanation:

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2 years ago

CAN YOU PLEASE HELP ME WITH THIS PROBLEM???

ozzi

Answer:

Step-by-step explanation:

$tan \ 50 =\dfrac{opposite \ side}{adjacent side}\\\\\\1.19=\dfrac{21}{MD}\\\\\\1.19*MD=21\\\\MD = \dfrac{21}{1.19}\\\\\\MD = 17.65$

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2 years ago

17) List the ways five dogs a Beagle, a Collie, a Greyhound, a Poodle and a

Gnoma [55]

Answer:

10 pairs

It is a combination

Explanation:

This is a combination because the order does not matter: the Beagle - Collie couple is the same as the Collie - Beagle couple, so it is only counted once.

The formula for combinations is:

$C(m,n)=\dfrac{m!}{n!\cdot (m-n)!}$

For five diffferent dogs to be put in pairs, the number of different pairs is:

$C(5,2)=\dfrac{5!}{2!\cdot (5-2)!}=\dfrac{5\times 4}{2}=10$

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3 years ago

Bonnie runs at an average speed 4 metres per second for 240 seconds.

telo118 [61]

Answer:

960 metres in 240 seconds.

Step-by-step explanation:

this is because they can run 4 metres every second.

the number of seconds they ran multiplied by the length of their run in a second is your answer.

240 x 4 = 960

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2 years ago

Read 2 more answers

What is 2logx−logy+2logz written as a single logarithm? log(xz)^2/y log2x/2yz logx^2y/z^2 logx^2/yz^2

Klio2033 [76]

Answer: $\log\dfrac{x^2z^2}{y}$

Step-by-step explanation:

Properties of logarithm:

$(i)\ \ n\log a = a^n\\\\ (ii)\ \ \log m +\log n =\log (mn)\\\\ (iii)\ \ \log m-\log n =\log\dfrac{m}{n}$

Consider,

$2\log x-\log y+2 \log z\\\\ =\log x^2-\log y+\log z^2\ \ \ \ \text{[By (i)]}\\\\= \log x^2+\log z^2-\log y\\\\=\log(x^2z^2)-\log y\ \ \ \ [\text{By } (ii) ]\\\\=\log(\dfrac{x^2z^2}{y}) \ \ \ \ [\text{By (iii)}]$

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3 years ago