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Tanya [424]
3 years ago
6

If f(x)=2x^2-x-6 and g(x)=x^2-4 find f(x)/g(x)

Mathematics
1 answer:
DENIUS [597]3 years ago
6 0
\dfrac{f(x)}{g(x)}=\dfrac{2x^2-x-6}{x^2-4}\\
\dfrac{f(x)}{g(x)}=\dfrac{2x^2-4x+3x-6}{(x-2)(x+2)}\\
\dfrac{f(x)}{g(x)}=\dfrac{2x(x-2)+3(x-2)}{(x-2)(x+2)}\\
\dfrac{f(x)}{g(x)}=\dfrac{(2x+3)(x-2)}{(x-2)(x+2)}\\
\dfrac{f(x)}{g(x)}=\dfrac{2x+3}{x+2}
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Answer:

∠2 = 55°

Step-by-step explanation:

Given that the triangle has 2 congruent sides then the triangle is isosceles.

Thus the 2 base angle are congruent, both equal to ∠2

The sum of the 3 angles in a triangle = 180

7x + 6 + 7x + 6 + 70 = 180, that is

14x + 82 = 180 ( subtract 82 from both sides )

14x = 98 ( divide both sides by 14 )

x = 7

Hence

∠2 = 7x + 6 = (7 × 7) + 6 = 49 + 6 = 55°

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Answer:

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Step-by-step explanation:

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Answer:

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