
<u>Let us assume that:</u>

We can also write it as:

Squaring both sides, we get:


By splitting the middle term:



<u>Therefore:</u>


<u>But x cannot be negative. </u>

Therefore, the value of the expression is 3.

Given:

We can also write it as:






This pattern will continue.

Answer:
38
Step-by-step explanation:
1/2(10p-7q)
1/2(10(9)-7(2))
1/2(90-14)
1/2(76)
76/2
38
Answer:
The first one
Step-by-step explanation:
The number line is supposed to show the product of 2 and five, the arrow will start at 0 because 5 times 0 is 0 then it will go to 5 because 5 times 1 is 5, then another arrow will start at 5 and point at 10 because 5 times 2 is 10
The second option points backwards which would be if you were dividing 10 by 5
The third option starts at negative 10 so it shows -10 divided by -5
the last option starts at 0 and goes to -10 so it shows -5 multiplied by 2
Black line (a) -
x = -2
Purple line (b) -
x = 3
Blue line (c) -
y = 6
Green line (d) -
y = -3
Red line (e) -
Not sure
Answer:
C.
Step-by-step explanation:
y = 1/ x must pass through the origin because when x = 0, y = 0.
So its either B or C.
A positive slope rises to the right ( 1/2 is positive), so its C.
You can also see that the slope of C is 1/2 because it passes through the points (0.0) and (2, 1).