<span>Give that </span>t<span>he frequency of G5 is 783.99 Hz.
To find the frequency of the note that is a perfect fifth above G5, we recall that </span>the frequencies of notes that are a 'perfect'
fifth apart are in the ratio of 1.5
i.e. <span>the frequency of the note that is a perfect fifth above G5 divided by </span><span>t<span>he frequency of G5 equal 1.5
Let the </span></span><span><span>frequency of the note that is a perfect fifth above G5 be F, then
F / </span>783.99 = 1.5
F = 1.5 x 783.99 = 1175.99
Therefore, </span>the <span>frequency of the note that is a perfect fifth above G5</span> is 1175.99 Hz
I really don’t know but maybe this will help you now and later
We know that
applying the law of sines
50/sin 40=60/sin x
50*sin x=60*sin 40
sin x=[60*sin 40]/50
sin x=0.7713
x=arc sin (0.7713)----> x=50.47°--------> x=50.5°
the answer is
x=50.5 °
Answer:
<h2>
The situation involves permutation</h2><h2>
The number of arrangement is 120</h2>
Step-by-step explanation:
Given that
Algebra book=1
Geometry book=1
Chemistry book= 1
English book= 1
Health book= 1
Total number of books N = (1+1+1+1+1)= 5
Permutation is used to determines the number of possible arrangements in a set when the order of the arrangements is crucial.
Number of arrangements = N!
Number of arrangements= 5*4*3*2*1= 120
A. -3x+5+7-4x
-3x-4x+5+7
-7x+12
-7x+12-5x+17
-7x-5x+12+17
-12x+29
B. -5*(x+2)= -5x-10
-6x-1+ (-5x-10)= -6x-5x-1-10=
-11x-11