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2 years ago

How many hours is 10:57p.m to 7:02a.m

1 answer:

5 0

This is what I do. There's another way if you want, though

ignore p.m. and a.m.

make second value, this case is 7:02, become 24-hour time.

so it would be 12+7:02, which is 19:02

now solve 10:57 to 19:02.

that is 8:05, or 8 hours and 5 minutes

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I need help pronto {(2,2,),(-5,2),(6,6),(9,4),(4,9)} is it a function and explain please

Mrac [35]

Answer:

yes, because the x values are all different. if the y values are the same it doesnt matter.

Step-by-step explanation:

6 0

2 years ago

Jason jumped of a cliff into the ocean . His height as a function off time could be models as h(t)=16tsquared + 16t + 480 where

Karo-lina-s [1.5K]

I see that you are in high school, and I'm hoping that you've been introduced
to differential calculus, because I don't know how to answer this question without
using it.

We're told that Jason's height above the water is H(t) = -16t² + 16t + 480 .
We can observe many things from this equation:
-- Up is the positive direction; down is the negative direction.
-- The acceleration of gravity is 32 ft/sec² .
-- Jason jumps upward from the cliff, at 16 ft/sec .
-- The cliff is 480-ft above the water.
(This tells us why the question is only concerned with his maximum height,
and then it ends ... 480-ft is one serious cliff, and what happens after the
peak of his arc is too gruesome to contemplate.)

In any case, his vertical velocity is the first derivative, with respect to time,
of his height above the water.

 V = -32 t + 16

At the peak of his arc, where gravity takes over, his velocity changes from
upward to downward, and it's momentarily zero.

 0 = -32t + 16

Add 32t to each side: 32t = 16

Divide each side by 32:  t = 1/2 second

His height at that instant is H(0.5) = -16(0.5)² + 16(0.5) + 480 =

 4-ft above the cliff, 484-ft above the water,

and then he begins falling from that altitude.

The duration of his dive is 484 = 16 t²
 t = √(484/16) = 5.5 seconds

and he hits the water at V = a t = (32) x (5.5) = 176 ft/sec = exactly 120 mph 

Jason was good man ... a good student, and always kind to everyone he met.
He will certainly be missed.

5 0

3 years ago

A researcher wants to construct a 90% confidence interval for the proportion of elementary school students in Seward County who

dezoksy [38]

Answer:

The sample size is $n =68$

Step-by-step explanation:

The population proportion is $\^ p = 0.50$

The margin of error is $E = 0.1$

From the question we are told the confidence level is 90% , hence the level of significance is

$\alpha = (100 - 90 ) \%$

=> $\alpha = 0.10$

Generally from the normal distribution table the critical value of $\frac{\alpha }{2}$ is

$Z_{\frac{\alpha }{2} } = 1.645$

Generally the sample size is mathematically represented as

$n = [\frac{Z_{\frac{\alpha }{2} }}{E} ]^2 * \^ p (1 - \^ p )$

=> $n = [\frac{1.645 }{0.1} ]^2 * 0.50 (1 - 0.50 )$

=> $n =68$

6 0

2 years ago

ANSWER AND EXPLAIN FOR BRAINLIEST :)

Ksenya-84 [330]

Answer: this is what i can tell you if it is a right triangle then you will di 90 - your numbers but if it is not a right triangel then you will do 180 instend then when you get the answer you add it with those numbers but not with the 90 or 180

Step-by-step explanation:

8 0

2 years ago

Read 2 more answers

Me podrían ayudar y explicarme el proceso please

kakasveta [241]

Answer: Encontrarás las respuestas debajo de cada explicación. Espero que consideres darme brainliest y 5 estrellas, y más importante, que hayas entendido.

Step-by-step explanation:

Esto es la regla de 3. Conoces 3 valores y necesitas encontrar un 4to valor.

Ya sabemos que 1 caja pesa 20kg,

1 - 20kg

ahora queremos saber cuantas cajas (x) equivalen a 7653kg

x - 7653kg

Hacemos un pequeño cuadro poniendo en un lado los numeros de cajas y del otro el peso.

Pongamos la cantidad de cajas en la izquierda y el peso en la derecha

$\frac{1}{x} =\frac{20kg}{7653kg}$

Procedemos a multiplicar en cruz. Solo podemos multiplicar si tenemos ambos valores. En este caso, los valores en cruz que tenemos son 1 y 7653kg porque en la otra cruz (20 y x) tenemos nuestra incognita. Y, por ultimo, dividimos entre el numero cuya cruz es con la incognita (20kg)

Esto nos deja la expresión así;

$x=\frac{1*7653kg}{20kg}$

$x=382.65$

Como una caja no puede ser un numero decimal, redondeamos.

$x=383$

Por lo tanto, se necesitan aproximadamente 383 cajas para que su peso equivalga a 7653 kg.

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La otra pregunta dice: Si una caja pesa 20kg, (1 - 20kg), ¿Cuántas cajas se necesitan para equivaler 9500kg? (x - 9500kg)

Hacemos lo mismo que arriba, ponemos la cantidad de cajas de un lado, y el peso de otro lado.

$\frac{1}{x}=\frac{20kg}{9500kg}$

Multiplicamos aquellos valores en cruz que conozcamos y dividimos por el valor cuya cruz sea con x.

$x=\frac{1*9500kg}{20kg}$

$x=475$

Esta es la cantidad de cajas que se necesitan para que su pesa equivalga a 9500kg.

--------------------------------------------------------------------------------------------------------

Por último, la pregunta dice, ¿Cuántos kilogramos hay en 873 cajas?

Ya sabemos que una caja pesa 20kg ( 1 - 20kg ) y ahora buscamos cuantos kg hay en 873 cajas; es decir, (873 - x)

Nos quedaría así;

$\frac{1}{873}=\frac{20kg}{x}$

Ahora, nuestra cruz es 873 y 20kg, y el divisor es 1.

$x=\frac{873*20kg}{1}$

$x=17460kg$

Este sería el peso de 873 cajas.

5 0

2 years ago