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3 years ago

? Solve for X 9x + 8 = -1

Mathematics

1 answer:

larisa [96]3 years ago

5 0

Answer:

x = -1

Step-by-step explanation:

9x + 8 = -1

Subtract 8 from each side

9x + 8-8 = -1-8

9x = -9

Divide each side by 9

9x/9 = -9/9

x = -1

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Fully factorise 8p + 12

77julia77 [94]

$8p+12=4(2p+3)$

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2 years ago

Read 2 more answers

True or false: the lateral surface of cone a is exactly 1/2 the lateral surface area of cylinder b

Mazyrski [523]

Answer:

True

Step-by-step explanation:

We have that,

The cone A has the length of the lateral side = h and the height of the cylinder B = h.

Since, the lateral surface areas are given by,

Lateral surface area of cone = $\pi r\times l$ , where l is the length of the lateral side.

So, we get $L_{A}$ = $\pi r\times h$ .

Also, Lateral surface area of cylinder is $2\pi r\times h$ , where h is the height of the cylinder.

So, we get $L_{B}$ = $2\pi r\times h$

Thus, we see that, $L_{A}=\frac{1}{2}\times L_{B}$

Hence, the given statement is correct.

6 0

3 years ago

let sin(θ) =3/5 and tan(y) =12/5 both angels comes from 2 different right trianglesa)find the third side of the two tringles b)

statuscvo [17]

In a right triangle, we haev some trigonometric relationships between the sides and angles. Given an angle, the ratio between the opposite side to the angle by the hypotenuse is the sine of this angle, therefore, the following statement

$\sin (\theta)=\frac{3}{5}$

Describes the following triangle

To find the missing length x, we could use the Pythagorean Theorem. The sum of the squares of the legs is equal to the square of the hypotenuse. From this, we have the following equation

$x^2+3^2=5^2$

Solving for x, we have

$\begin{gathered} x^2+3^2=5^2 \\ x^2+9=25 \\ x^2=25-9 \\ x^2=16 \\ x=\sqrt[]{16} \\ x=4 \end{gathered}$

The missing length of the first triangle is equal to 4.

For the other triangle, instead of a sine we have a tangent relation. Given an angle in a right triangle, its tanget is equal to the ratio between the opposite side and adjacent side.The following expression

$\tan (y)=\frac{12}{5}$

Describes the following triangle

Using the Pythagorean Theorem again, we have

$5^2+12^2=h^2$

Solving for h, we have

$\begin{gathered} 5^2+12^2=h^2 \\ 25+144=h^2 \\ 169=h^2 \\ h=\sqrt[]{169} \\ h=13 \end{gathered}$

The missing side measure is equal to 13.

Now that we have all sides of both triangles, we can construct any trigonometric relation for those angles.

The sine is the ratio between the opposite side and the hypotenuse, and the cosine is the ratio between the adjacent side and the hypotenuse, therefore, we have the following relations for our angles

$\begin{gathered} \sin (\theta)=\frac{3}{5} \\ \cos (\theta)=\frac{4}{5} \\ \sin (y)=\frac{12}{13} \\ \cos (y)=\frac{5}{13} \end{gathered}$

To calculate the sine and cosine of the sum

$\begin{gathered} \sin (\theta+y) \\ \cos (\theta+y) \end{gathered}$

We can use the following identities

$\begin{gathered} \sin (A+B)=\sin A\cos B+\cos A\sin B \\ \cos (A+B)=\cos A\cos B-\sin A\sin B \end{gathered}$

Using those identities in our problem, we're going to have

$\begin{gathered} \sin (\theta+y)=\sin \theta\cos y+\cos \theta\sin y=\frac{3}{5}\cdot\frac{5}{13}+\frac{4}{5}\cdot\frac{12}{13}=\frac{63}{65} \\ \cos (\theta+y)=\cos \theta\cos y-\sin \theta\sin y=\frac{4}{5}\cdot\frac{5}{13}-\frac{3}{5}\cdot\frac{12}{13}=-\frac{16}{65} \end{gathered}$

4 0

1 year ago

On a coordinate plane, a parabola opens up. It goes through (negative 2, 4), has a vertex at (0.25, negative 6), and goes throug

serg [7]

The statements true about the the function f(x) = 2x2 – x – 6 are-

The vertex of the function is (one-quarter, negative 6 and one-eighth).
The function has two x-intercepts.

<h3>What is vertex of parabola?</h3>

The vertex of parabola is the point at the intersection of parabola and its line of symmetry.

Now the given function is,

f(x) = 2x^2 – x – 6

Also, it is given that the vertex is located at (0.25, -6) and the parabola opens up, the function has two x-intercepts.

Comparing the given function with standard form,

f(x) = a x^2 bx + c

By comprison we get,

a = 2

b = -1

c = -6

Now, x-coordinate of vertex is given as,

x = -b/2a

put the values we get,

x = -(-1)/2*2

or, x = 1/4

Put the value of x in given function, so y-coordinate of the vertex is given as,

f(1/4) = 2(1/4)² - 1/4 - 6

= -49/6

= -6 1/8

Hence, The statements true about the the function f(x) = 2x2 – x – 6 are-

The vertex of the function is (one-quarter, negative 6 and one-eighth).
The function has two x-intercepts.

More about vertex :

brainly.com/question/86393

#SPJ1

3 0

2 years ago

Is 0.35 grater than 300 mL

Sveta_85 [38]

Answer:

yes

Step-by-step explanation:

yes

6 0

3 years ago